Determing where function is differentiable (Complex Analysis)

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Homework Help Overview

The discussion revolves around determining where the function f, defined as f(x + iy) = 1/(x + i3y), is differentiable in the context of complex analysis. Participants are exploring the implications of the Cauchy-Riemann equations on the differentiability of the function.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the Cauchy-Riemann equations and question whether the function can be differentiable at any point. There are attempts to derive conditions for differentiability by equating partial derivatives.

Discussion Status

The conversation is ongoing, with participants examining the conditions under which the Cauchy-Riemann equations hold. Some guidance has been provided regarding the relationship between the equations and differentiability, but there remains uncertainty about the implications of their findings.

Contextual Notes

Participants are grappling with the potential for the function to be undefined at certain points, particularly at the origin, which raises questions about the overall differentiability of the function.

scothoward
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Homework Statement


Determine where the function f has a derivative, as a function of a complex variable:

f(x +iy) = 1/(x+i3y)


The Attempt at a Solution



I know the cauchy-riemann is not satisfied, so does that simply mean the function is not differentiable anywhere?
 
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No. Where Cauchy-Riemann is satisfied, the function is differentiable. There could be some places. Are there?
 
Hmm I was thinking, maybe I could take the partials of U and V (Cauchy-Riemann) equate them, and find out what x,y have to be in order for the equations to be satisfied. Am I on the right track?
 
Yes, if CR is satisfied at a point, then the function is differentiable at that point. That's where CR comes from.
 
Last edited:
Alright, so doing the partials and equating I get

x = 3y and
xy = 3xy

But, I am a little confused on what to do from here.

Thanks for the help
 
Thinking about it a little more, would this mean when x = 3y, the function is differentiable and when either x=0, y=0, the function is differentiable? Or is my thinking wrong?
 
IF that's right then putting the first equation into the second gives 3y^2=9y^2, so y=0. If y=0 then x=0. So differentiable only at 0+0i.
 
Thanks for the help Dick!

Just to clarify one more thing. Presuming that I did calculate the paritals right and that leads to 0 + i0, wouldn't that lead to the original function being undefined? As a result, wouldn't the function be differentiable no where?
 
Very astute, scothoward. I was on my way to missing that.
 

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