Determining Age of Universe w/ Hubbles Constant

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SUMMARY

The age of the universe can be determined using Hubble's Constant, specifically the current value of 71 km/s/Mpc. By applying the formula T = 1012/H, where H represents the Hubble constant, the calculated Hubble time yields approximately 14 billion years. Additionally, the relationship between velocity and distance is expressed as v = H * X, where X is the current radius of the universe. Consequently, the age of the universe is the inverse of the Hubble constant, reinforcing the direct correlation between these cosmological parameters.

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  • Basic knowledge of the Big Bang theory
  • Familiarity with the concept of cosmic expansion
  • Ability to perform basic mathematical calculations involving constants and units
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Please can somebody explain how the age of the universe can be determined using Hubbles Constant?
If the constant is taken as 10km/s (just for the sake of easiness), how can this be figured out using calculations?

I appreciate any help!:smile:
 
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the current value of Hubble constant is 71km/s/Mpc,now if you want to calculate the Hubble time, that is the time that have passed since Big bang, you do:
T=1012/H
where H is the Hubble constant, the result gives the Hubble time in years. If I put 71 in H, if gives 14 billion of years
From the formula you can see that the Hubble constant diminish in value with time, as the Hubble time augments
 
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From the center of universe when you look the outer most particle the velocity will be

v=H*X ---- X - Current radius of universe.

So the time of that particle to reach there(age of universe) is

X/V

Which is 1/H

That's it.. Age of universe is Inverse Of H..
This is the most silliest way of explaining it..
 

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