Determining Basic and Free Variables in a Linear System

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SUMMARY

The forum discussion focuses on determining basic and free variables in a linear system represented by an augmented matrix. The user initially provided an incorrect row echelon form after performing several row operations. The correct row echelon form is confirmed as [[1, -1, -1, 4], [0, 1, 1/2, -1], [0, 0, 0, 0]]. Basic variables correspond to the leading 1s in each row, while free variables are those that do not have a leading 1 in their respective columns.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically row echelon form.
  • Familiarity with augmented matrices and their manipulation.
  • Knowledge of basic and free variables in linear systems.
  • Proficiency in performing fundamental row operations.
NEXT STEPS
  • Study the concept of row echelon form in linear algebra.
  • Learn about basic and free variables in the context of linear systems.
  • Practice solving linear equations using augmented matrices.
  • Explore software tools like MATLAB or Python's NumPy for matrix operations.
USEFUL FOR

Students and educators in mathematics, particularly those studying linear algebra, as well as anyone involved in solving systems of equations and understanding matrix theory.

amcgl064
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Find the general solution to the following system of equations and indicate which variables are free and which are basic.

png.latex

png.latex

png.latex


Putting it in augmented matrix form to start we have:
1 -1 -1 4 | -3
1 0 -1/2 3 | -1
1 1 0 2 | 1

Now performing the following fundamental row operations:

R1<-->R2
R2+R3-->R2
-2R3+R2-->R2
-R3+R1-->R3
R2/-2
R2+R3-->R2
-3R3+R1-->R1

And finally I end with the augmented matrix:

1 0 -2 0 | 5
0 1 0 0 | 0
0 0 -1/2 1 |-2

Can someone please tell me if I got the correct matrix at the end and if so how do I determine which variables are free and which are basic?

Thank you.
 
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amcgl064 said:
Find the general solution to the following system of equations and indicate which variables are free and which are basic.

png.latex

png.latex

png.latex


Putting it in augmented matrix form to start we have:
1 -1 -1 4 | -3
1 0 -1/2 3 | -1
1 1 0 2 | 1

Now performing the following fundamental row operations:

R1<-->R2
R2+R3-->R2
-2R3+R2-->R2
-R3+R1-->R3
R2/-2
R2+R3-->R2
-3R3+R1-->R1

And finally I end with the augmented matrix:

1 0 -2 0 | 5
0 1 0 0 | 0
0 0 -1/2 1 |-2

Can someone please tell me if I got the correct matrix at the end and if so how do I determine which variables are free and which are basic?

Thank you.

Hi amcgl064, :)

The answer you have obtained for the row echelon form is incorrect. The correct answer is,

\[\left(\begin{matrix}1&-1&-1&4\\0&1&\frac{1}{2}&-1\\0&0&0&0\end{matrix}\right)\]

Please refer >>this<< for a basic introduction about basic variables and free variables. I hope you can do the rest. :)

Kind Regards,
Sudharaka.
 

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