Determining Direction of Magnetic Force on a Moving Bar Magnet Near a Wire Loop

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SUMMARY

The discussion focuses on determining the direction of magnetic force on a bar magnet moving near a circular wire loop. The induced current in the wire is clockwise in cases B and C, and counterclockwise in cases A and D. Utilizing the right-hand rule, it is established that the north pole of the magnet experiences an upward force when moving towards the loop due to the upward magnetic field created by the loop. Conversely, the south pole experiences a downward force, but the net force on the magnet is upward, confirming the repulsion between like poles.

PREREQUISITES
  • Understanding of electromagnetic induction and Faraday's Law
  • Familiarity with the right-hand rule for magnetic forces
  • Knowledge of magnetic field direction in loops of wire
  • Basic concepts of magnetic poles and their interactions
NEXT STEPS
  • Study the application of Faraday's Law in different electromagnetic scenarios
  • Learn about the right-hand rule in various contexts of electromagnetism
  • Explore the effects of magnetic field strength on induced currents
  • Investigate the principles of magnetic repulsion and attraction in detail
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Physics students, educators, and anyone interested in understanding the principles of electromagnetism and magnetic interactions in circuits.

nickr96
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Homework Statement


A bar magnetic is moved along the axis of a circular wire loop. In the figure below, (A) and (C) show the bar magnet moving toward the wire loop, while (B) and (D) show the bar magnet moving away from the wire loop.
Image: https://gyazo.com/2944a79393e7955214b281da58e7b0b8
Trying to determine in which cases the direction of magnetic force on the bar magnent is up and in which cases it is down.

Homework Equations


Not trying to determine any actual values, just direction.

The Attempt at a Solution


I've already determined that in cases B and C the induced current in the wire is clockwise and in cases A and D the induced current in the wire is counterclockwise. However I'm unsure as to how to use this information in the correct way to determine the direction of magnetic force acting on the bar magnet. It almost certainly has to do with the right-hand rule, given that I know both the direction of the induced current and magnetic field in the loop. However, because it is a loop of wire in cases A and D the magnetic field is flowing "up" inside and loop and "down" outside the loop, and vice versa for cases B and C. As such, I'm unsure what the direction of the magnetic field should be when trying to utilize the right-hand rule.
 
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nickr96 said:

The Attempt at a Solution


I've already determined that in cases B and C the induced current in the wire is clockwise and in cases A and D the induced current in the wire is counterclockwise.
OK, sounds good.
However I'm unsure as to how to use this information in the correct way to determine the direction of magnetic force acting on the bar magnet. It almost certainly has to do with the right-hand rule, given that I know both the direction of the induced current and magnetic field in the loop. However, because it is a loop of wire in cases A and D the magnetic field is flowing "up" inside and loop and "down" outside the loop, and vice versa for cases B and C. As such, I'm unsure what the direction of the magnetic field should be when trying to utilize the right-hand rule.
What's important is the loop's magnetic field at the location of the bar magnet. Imagine a bar magnet placed above the loop shown here:
http://ipodphysics.com/magnets-loop-or-coil.php
If the magnet is oriented as in case (A) in your problem, can you see what direction the force on the magnet would be?
 
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TSny said:
OK, sounds good.

What's important is the loop's magnetic field at the location of the bar magnet. Imagine a bar magnet placed above the loop shown here:
http://ipodphysics.com/magnets-loop-or-coil.php
If the magnet is oriented as in case (A) in your problem, can you see what direction the force on the magnet would be?

Okay, so I'm unsure of how the magnetic field produced by the magnet and the magnetic field produced by the induced current interact. Is this actually simply a problem of repulsion and attraction? In the picture you linked, the induced magnetic field is the same as in case A, so if you were moving the north end of the magnet down towards the loop, it's akin to moving the north ends of two magnets together, in which case they'd repel and for the case of the loop the magnet would be repelled from the loop, indicating an "upward" direction of motion in relation to the loop. Is this the correct way of thinking about the problem?
 
nickr96 said:
Is this actually simply a problem of repulsion and attraction? In the picture you linked, the induced magnetic field is the same as in case A, so if you were moving the north end of the magnet down towards the loop, it's akin to moving the north ends of two magnets together, in which case they'd repel and for the case of the loop the magnet would be repelled from the loop, indicating an "upward" direction of motion in relation to the loop. Is this the correct way of thinking about the problem?
Yes, that's a good way to think about it.

Another way is to realize that a N-pole of a magnet always feels a magnetic force in the direction of the B field that the N-pole is placed in. Since the loop's magnetic field is upward at the location of the N-pole, the N-pole will experience an upward force. Of course, the S-pole of the magnet will feel a force opposite to the direction of the loop's field. So, the S-pole of the magnet will feel a force downward at the same time that the N-pole feels a force upward. But the force on the N-pole is stronger than the force on the S-pole because the S-pole is farther from the loop (where the loop's field is weaker). So the net force on the magnet is upward. Whew!

You might prefer to stick with your way. But it's good practice to see it in different ways.
 
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TSny said:
Yes, that's a good way to think about it.

Another way is to realize that a N-pole of a magnet always feels a magnetic force in the direction of the B field that the N-pole is placed in. Since the loop's magnetic field is upward at the location of the N-pole, the N-pole will experience an upward force. Of course, the S-pole of the magnet will feel a force opposite to the direction of the loop's field. So, the S-pole of the magnet will feel a force downward at the same time that the N-pole feels a force upward. But the force on the N-pole is stronger than the force on the S-pole because the S-pole is farther from the loop (where the loop's field is weaker). So the net force on the magnet is upward. Whew!

You might prefer to stick with your way. But it's good practice to see it in different ways.
Thanks for your help!
 

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