Determining domain for C^1 function

Click For Summary
SUMMARY

The discussion centers on determining the domain of a function \( f \) that is \( C^1 \) based on its partial derivatives. The partial derivatives with respect to \( x \) and \( y \) are given as \( L \frac{4x}{5(x^{2}+y^{2})^{\frac{-3}{5}}} \) and \( L \frac{4y}{5(x^{2}+y^{2})^{\frac{-3}{5}}} \), respectively. It is established that these derivatives do not exist at the origin, confirming that \( f \) is not \( C^1 \) at that point, while being \( C^1 \) elsewhere due to continuity of the composition of polynomials. The reasoning presented is accurate and highlights the critical nature of differentiability at specific points.

PREREQUISITES
  • Understanding of partial derivatives and their definitions
  • Familiarity with the concept of \( C^1 \) functions
  • Knowledge of polynomial functions and their continuity properties
  • Basic proficiency in LaTeX for mathematical notation
NEXT STEPS
  • Study the properties of \( C^1 \) functions in multivariable calculus
  • Learn about the limit definition of partial derivatives
  • Explore the implications of differentiability at points of inflection
  • Practice using LaTeX for mathematical expressions in discussions
USEFUL FOR

Mathematicians, calculus students, and educators focusing on multivariable calculus and the properties of differentiable functions.

lys04
Messages
144
Reaction score
5
Homework Statement
Picture
Relevant Equations
Partial derivatives
The ####x partial derivative is equal to $$L \frac{4x}{5(x^{2}+y^{2})^{\frac{-3}{5}}}$$ and the partial for ##y## is $$L \frac{4y}{5(x^{2}+y^{2})^{\frac{-3}{5}}}$$
Using the limit definition of partial derivatives I got the partial wrt ##x## is $$L \frac{h^{\frac{4}{5}}}{h}$$ which doesn’t exist as ##h## goes to ##0##. Similar argument for partial wrt ##y##. This means that ##f## isn’t ##C^1## at the origin, right?

At every other point the partial derivatives exist and is continuous because it’s a composition of a polynomial of two variables and ##x^2/5##, so ##f## is ##C^1## at all points except the origin.

Is the reasoning correct?
IMG_0425.jpeg
 
Last edited by a moderator:
Physics news on Phys.org
I don’t think latex is working, not sure what’s wrong with it sorry
 
lys04 said:
I don’t think latex is working, not sure what’s wrong with it sorry
One problem is that { and } don't match.
 
Works very well with the additional }:

$$L \frac{4x}{5(x^{2}+y^{2})^{\frac{-3}{5}}}$$
 
\sqrt[2n+1]{x} is not differentiable at x = 0 for n \geq 1. This follows from the fact that x^{2n+1} has a point of inflection here.
 

Similar threads

Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
5
Views
2K
Replies
9
Views
2K