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Determining Liters of ethane burned to convert H20 to steam

  1. Jun 4, 2015 #1
    1. The problem statement, all variables and given/known data
    The Heat of combustion of Ethane is 373 kcal/mole. Assuming that 60% of the heat is useful , how many liters of ethane,, measured at standard temperature and pressure, must be burned to convert 50.0kg of water ar 10.0C to steam at 100.0C? One mole of a gas occupies 22.4 liters at precisely 0C and 1atm.

    2. Relevant equations
    PV=nRT Q=mcΔT


    3. The attempt at a solution
    Qburned=Q heat up

    =mL + mcΔT

    540g/C(50g)+ 50(1cal/gC)(100-10)
    Q=31500 cal

    n= Q/heat of combustion(60%)
    n=0.1407mol

    PV=nRT
    V=0.1407mol(8314j/kmolK)(273K)/1atm

    V=3193680 L

    The book has it at 315000. Is there something wrong here? I feel like im missing a term or left something out???
     
  2. jcsd
  3. Jun 5, 2015 #2

    NascentOxygen

    User Avatar

    Staff: Mentor

    You calculated Qburned per 50 grams. Did you convert this to per 50 kg somewhere?
     
  4. Jun 5, 2015 #3
    Why use PV=nRT when you're given 22.4 L/mol?
     
  5. Jun 5, 2015 #4
    Ahh that's where the error comes from. I forgot that it is per mole
     
  6. Jun 5, 2015 #5
    I did I believe. It should be in my note pad
     
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