Determining magnitude of net force with three parallel wires

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To determine the net force on the bottom wire in a system of three parallel wires carrying currents of 3 A, 2 A, and 1 A, the magnetic field contributions from the other wires must be calculated at the position of the bottom wire. The distances used for these calculations are 3r for the first wire and 2r for the second wire. The magnetic fields generated by the first and second wires at the location of the third wire need to be summed to find the net magnetic field. The right-hand rule is applied to ascertain the direction of the forces, which may lead to cancellation. Ultimately, the expected result for the net force on the bottom wire is 0 N.
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Homework Statement


Three parallel wires carry a current of I 1 = 3 A, I 2 = 2 A, and I 3 = 1 A, respectively. They are arranged as shown. If r = 2m and L=5m,what is the magnitude of the net force on the bottom wire?
<------------------------- I1
r
-------------------------->I2

2r

<--------------------------I3

I1 = 3A I2 = 2A I3 = 1A r = 2m L = 5m
They show the radius from I1-->I2 as r and the radius from I1-->I3 as 3r(a) 0 N
(b) 5×10−7 N
(c) 2×10−7 N
(d) 3×10−7 N

Homework Equations


F = ILBcosθ
B = μo * I/ 2∏r

The Attempt at a Solution



I feel like I am missing a concept here.

B = (1.257e-6)(1A)/2(Pi)(2) = 1.00028e-7
F = ILB = (1)(5)(1.00028e-7) = 5.0014e-7

The answer is supposed to be 0N. I was thinking the first two wires might cancel out, but I am really not too sure. I don't see any other concepts. I also tried the right hand rule to determine the direction of Force. I feel pretty lost at this point.
 

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mevalle said:
B = μo * I/ 2∏r
This, with the right hand rule, is what you need.

Hints:
When figuring out the B field at I3 due to I1, what distance will you use? What value of I?

When figuring out the B field at I3 due to I2, what distance will you use? What value of I?
 
The distance used with I3 would be 3r and I2 would be 2r? The Current for I3 being 3A and for I2 being 2A, right?
 
mevalle said:
The distance used with I3 would be 3r and I2 would be 2r?
I'll reword that. We want to calculate the B field created by I1 at the position of wire 3. So we need the distance between wire 1 and wire 3, which is 3r.

And we also want to calculate the B field created by I2 at the position of wire 3. So we need the distance between wire 2 and wire 3, which is 2r.
The Current for I3 being 3A and for I2 being 2A, right?
When finding the B field due to wire 1, we use the current I1 (which is 3 A). When finding the B field due to wire 2, we use the current I2 (which is 2 A).

So find the magnitude and direction of those two B field contributions. Then you can add them up to find the net B field at wire 3 due to the other two currents.
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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