Determining magnitude of net force with three parallel wires

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Homework Help Overview

The problem involves three parallel wires carrying different currents and seeks to determine the magnitude of the net force on the bottom wire. The subject area includes electromagnetism, specifically the interactions between current-carrying wires and the magnetic fields they produce.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of the magnetic field at the position of the bottom wire due to the other two wires, questioning the distances and currents to be used in the calculations. There is uncertainty about the cancellation of forces and the application of the right-hand rule.

Discussion Status

Some participants have offered hints regarding the distances and currents to consider when calculating the magnetic fields. There is an ongoing exploration of the contributions of each wire to the net magnetic field at the position of the bottom wire, with no explicit consensus reached yet.

Contextual Notes

Participants are navigating the complexities of the problem, including the distances between wires and the effects of the currents involved. The original poster expresses feeling lost and uncertain about the concepts required to solve the problem.

mevalle
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Homework Statement


Three parallel wires carry a current of I 1 = 3 A, I 2 = 2 A, and I 3 = 1 A, respectively. They are arranged as shown. If r = 2m and L=5m,what is the magnitude of the net force on the bottom wire?
<------------------------- I1
r
-------------------------->I2

2r

<--------------------------I3

I1 = 3A I2 = 2A I3 = 1A r = 2m L = 5m
They show the radius from I1-->I2 as r and the radius from I1-->I3 as 3r(a) 0 N
(b) 5×10−7 N
(c) 2×10−7 N
(d) 3×10−7 N

Homework Equations


F = ILBcosθ
B = μo * I/ 2∏r

The Attempt at a Solution



I feel like I am missing a concept here.

B = (1.257e-6)(1A)/2(Pi)(2) = 1.00028e-7
F = ILB = (1)(5)(1.00028e-7) = 5.0014e-7

The answer is supposed to be 0N. I was thinking the first two wires might cancel out, but I am really not too sure. I don't see any other concepts. I also tried the right hand rule to determine the direction of Force. I feel pretty lost at this point.
 

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mevalle said:
B = μo * I/ 2∏r
This, with the right hand rule, is what you need.

Hints:
When figuring out the B field at I3 due to I1, what distance will you use? What value of I?

When figuring out the B field at I3 due to I2, what distance will you use? What value of I?
 
The distance used with I3 would be 3r and I2 would be 2r? The Current for I3 being 3A and for I2 being 2A, right?
 
mevalle said:
The distance used with I3 would be 3r and I2 would be 2r?
I'll reword that. We want to calculate the B field created by I1 at the position of wire 3. So we need the distance between wire 1 and wire 3, which is 3r.

And we also want to calculate the B field created by I2 at the position of wire 3. So we need the distance between wire 2 and wire 3, which is 2r.
The Current for I3 being 3A and for I2 being 2A, right?
When finding the B field due to wire 1, we use the current I1 (which is 3 A). When finding the B field due to wire 2, we use the current I2 (which is 2 A).

So find the magnitude and direction of those two B field contributions. Then you can add them up to find the net B field at wire 3 due to the other two currents.
 

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