Power produced from alpha decay

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Homework Help Overview

The discussion revolves around calculating the power produced from the alpha decay of a 14 kg sample of 240Pu, considering the efficiency of the device used for power generation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the energy released per decay and the number of plutonium atoms in the sample. There is an attempt to convert energy from MeV to Joules and to account for efficiency. Questions arise regarding the decay rate and the half-life of Pu-240.

Discussion Status

Participants are exploring the relationship between the decay rate and the energy produced. Some have provided calculations for energy per decay, while others are questioning the necessary information about the decay rate to proceed further.

Contextual Notes

There is a mention of the half-life of Pu-240 being approximately 6560 years, which is relevant for determining the decay rate needed for power calculations.

MattHorbacz
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Homework Statement


Assume that a 14 kg sample of 240Pu is used to produce electrical power from its α decay. If your device is 60% efficient in producing electrical power, how much power can be produced? (in watts)

Homework Equations


Q=mass of plutonium-mass alpha-mass daughter; 240 plutonium= alpha +uranium236

The Attempt at a Solution


I found Q to be 5.25572 Mev. The number of Plutonium atoms is 14*10^3 grams * 6.022*10^23/240. Multiply this by Q to get total energy in ev. Then multiply by 1.602176565e-19 to get in terms of Joules. Then multiply by .6, and that's where I get stuck. No idea how to get to watts. the answer should be 59.4 watts.
 
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MattHorbacz said:

Homework Statement


Assume that a 14 kg sample of 240Pu is used to produce electrical power from its α decay. If your device is 60% efficient in producing electrical power, how much power can be produced? (in watts)

Homework Equations


Q=mass of plutonium-mass alpha-mass daughter; 240 plutonium= alpha +uranium236

The Attempt at a Solution


I found Q to be 5.25572 Mev. The number of Plutonium atoms is 14*10^3 grams * 6.022*10^23/240. Multiply this by Q to get total energy in ev. Then multiply by 1.602176565e-19 to get in terms of Joules. Then multiply by .6, and that's where I get stuck. No idea how to get to watts. the answer should be 59.4 watts.

You need to know how quickly Pu-240 decays. Do you know the half-life of Pu-240?
 
I looked it up at it seems to be about 6560 years
 
MattHorbacz said:
I looked it up at it seems to be about 6560 years
OK, from that, you need to figure out how many atoms of Pu-240 are decaying each second in your original 14 kg of this substance.

Knowing that, you have already computed how much energy is released with each decay, so finding the power should be trivial.
 
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