Determining Oxidation Numbers of KClO3, NH4+, Cr2O72-, MnO42-

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SUMMARY

The oxidation numbers for the compounds discussed are as follows: in KClO3, chlorine (Cl) has an oxidation number of +5, potassium (K) is +1, and oxygen (O) is -2. For the ammonium ion (NH4+), nitrogen (N) has an oxidation number of -3, while hydrogen (H) is +1. In the dichromate ion (Cr2O72-), chromium (Cr) has an oxidation number of +6, and in the manganate ion (MnO42-), manganese (Mn) has an oxidation number of +6. These values are derived from established oxidation number rules, ensuring that the overall charge of the molecule or ion is balanced.

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Determine the oxidation numbers of the underlined elements in the following formulas:?
If you could explain each one, it would be greatly appreciated. Thanks!
a) KClO3
b) NH4+
c) Cr2O72-
d) MnO42-
 
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Okay is a) +5 because K=+1 and O=-2? I'm just wondering cause someone posted that on yahoo.
 
Yep, Cl in KClO3 is +5 (regardless of what was posted on Yahoo).

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do you think you could explain to me why?
 
Because it can be calculated following rules from the page I have linked to?

Nothing magic about it. Molecule is neutral, K is +1 (one of the rules), O is -2 (one of the rules), so Cl+1+3*(-2)=0.

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methods
 

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