Determining Oxidation Numbers of KClO3, NH4+, Cr2O72-, MnO42-

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Discussion Overview

The discussion focuses on determining the oxidation numbers of specific elements in various chemical formulas: KClO3, NH4+, Cr2O72-, and MnO42-. Participants seek clarification and explanations regarding the calculation of these oxidation states, exploring the underlying rules and reasoning.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests that the oxidation number of Cl in KClO3 is +5, based on the assumption that K is +1 and O is -2.
  • Another participant confirms the +5 oxidation state for Cl, stating it is independent of external sources like Yahoo.
  • A request for further explanation on the reasoning behind the oxidation number calculations is made.
  • A participant explains that the oxidation number can be calculated using established rules, emphasizing that the molecule is neutral and providing a formula to illustrate the calculation.

Areas of Agreement / Disagreement

Participants generally agree on the oxidation number of Cl in KClO3 being +5, but there is a request for further clarification on the reasoning, indicating that some aspects of the discussion remain unresolved.

Contextual Notes

The discussion relies on specific rules for calculating oxidation numbers, which may not be universally agreed upon or fully detailed in the posts. The assumptions made about the oxidation states of K and O are based on common conventions that may vary in different contexts.

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Determine the oxidation numbers of the underlined elements in the following formulas:?
If you could explain each one, it would be greatly appreciated. Thanks!
a) KClO3
b) NH4+
c) Cr2O72-
d) MnO42-
 
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Okay is a) +5 because K=+1 and O=-2? I'm just wondering cause someone posted that on yahoo.
 
Yep, Cl in KClO3 is +5 (regardless of what was posted on Yahoo).

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do you think you could explain to me why?
 
Because it can be calculated following rules from the page I have linked to?

Nothing magic about it. Molecule is neutral, K is +1 (one of the rules), O is -2 (one of the rules), so Cl+1+3*(-2)=0.

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methods
 

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