Determining the change in temperature

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SUMMARY

The discussion focuses on calculating the energy output of a group of people and the resulting temperature change in a room. A person emits 200W of heat, leading to a total energy release of 3.24 x 107 Joules from 45 people over one hour. The temperature change in a 300 m3 room filled with air, given a specific heat capacity of 1020 J/K·kg and a density of 1.20 kg/m3, was incorrectly calculated as 60 Kelvin. The correct approach involves accurately determining the mass of the air and applying the formula Q=Mc(ΔT) correctly.

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Homework Statement



A person sitting in a room has a heat output of 200W. Please calculate...

A) How much energy does a room of 45 people release over a course of 1 hour?
B) Assuming that all the energy in part a is transferred to a room of 300 M^3 of air. The air has a specific heat capacity of 1020 J/KxKg and density of 1.20. If none of the heat escapes, how much will the temperature change over time of 50 minutes?

Homework Equations





The Attempt at a Solution



For part A I found that the energy would be 45x200x3600 seconds = 3.24 x 10^7

For part B however, I tried to determine the mass by rearranging the density formula, multiplying density by volume. using that number in Q=Mc (delta T), and rearranging the formula, i get a change of around 60 Kelvin. But I know that can't be right...What am I doing wrong?
 
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Can you show us exactly how you got the temperature change to be 60 K? Then maybe we could figure out what you are doing wrong.
 

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