Determining the density of a stellar object

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SUMMARY

The discussion centers on calculating the mean density of Callisto, a moon of Jupiter, using the formula for density (p = m/v) and the volume of a sphere (V = 4/3πr³). The user initially arrives at an incorrect density value of 1.851238398 x 10⁹ kg/m³, which is one million times too large due to a unit conversion error when calculating volume from cubic kilometers to cubic meters. The correct volume conversion reveals that 1 km³ equals 10⁹ m³, leading to the accurate density calculation.

PREREQUISITES
  • Understanding of basic physics concepts, specifically density and volume calculations.
  • Familiarity with the formula for the volume of a sphere: V = 4/3πr³.
  • Knowledge of unit conversions, particularly between kilometers and meters.
  • Ability to perform calculations in scientific notation.
NEXT STEPS
  • Review unit conversion techniques, especially for volume measurements (km³ to m³).
  • Practice density calculations using different celestial bodies' mass and volume.
  • Explore the significance of significant figures in scientific calculations.
  • Learn about the properties of celestial bodies, focusing on density variations among planets and moons.
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Students studying physics, particularly those tackling problems related to celestial mechanics and density calculations, as well as educators looking for examples of common calculation errors in physics.

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Homework Statement


Hello all. I am new to physics but am quite competent in maths and other sciences. I am studying Open University's Exploring Science module and this one question has me stumped. I follow all of the instructions but always come to a completely improbable answer. The interesting thing is, that if I divide my answer by 1 million I get the correct answer, which makes me think that I have missed out a line of working somewhere along the line. I looked at the densities of the planets in our Solar System and tried to get the correct answer by the same calculations. Once again, my answer is one million times to large! I was hoping someone with a bit more experience in the field could shed some light for me. The question is:

Callisto, one of the satellites of the planet Jupiter, has a mean radius of
2403 km and a mass of 1.076 × 10 to the power 23 kg. Calculate its mean density in kg m
(i.e. SI units), giving your answer in scientific notation to the appropriate
number of significant figures and showing all of your working


Homework Equations



V= 4/3πr3 and p = m/v


The Attempt at a Solution




Cube the radius: (2403km)3 = 1.387590483 x 1010
Multiply that answer by 4: 1.387590483 x 4 = 5.550361931 x 1010
Multiply that answer by π: 5.550361931 x π = 1.743697627 x 1011
Divide that answer by 3: 1.743697627 x 1011 / 3 = 5.812325422 x 1010
Volume of Callisto = 5.812325422 x 1010 km3 = 5.812325422 x 1013 m3

Now that the volume is known - and the mass is provided in the question (1.076 x 1023 kg) - the density can be calculated by the following formula:

Density = mass/volume = (1.076 ×〖10〗^23 kg)/(5.812325422 × 〖10〗^(13 ) m^3 ) = 1.851238398 x 109 kg m-3

If I divide this answer by 1 million, I get the correct answer. But I don't know why!
 
Physics news on Phys.org
One km^3 is (10^3 m)^3 = 10^9 m^3, not 10^3 m^3 This is your problem.
 
Thanks phyzguy, feel a bit stupid now!
 

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