Determining the direction of current due to a change in magnetic flux

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SUMMARY

The discussion centers on the determination of current direction due to a change in magnetic flux, specifically in a scenario involving a declining magnetic field in the -z direction. The consensus is that the induced current should be clockwise when viewed from above the x-y plane, opposing the change in magnetic flux. This conclusion aligns with Lenz's Law, which states that the induced current will always act to oppose the change in magnetic field. The terminology used in the discussion is noted to be confusing, particularly regarding the perspective from which the current direction is observed.

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  • Understanding of Lenz's Law
  • Familiarity with magnetic flux concepts
  • Knowledge of current direction conventions in electromagnetism
  • Basic principles of chirality in chemistry
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Eitan Levy
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Homework Statement
Let there be a magnetic field as posted below.

There is a square shaped loop with its center being at (2a, 2a,0). The length of the sides is 2a.

The loop is placed in the xy plane (z=0).

Determine the direction of the current in the loop.
Relevant Equations
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1602616068556.png


This is supposed to be very basic, where the loop is held there is a declining magnetic field in direction (-z), therefore the current is supposed to be clockwise. However in the answers it is said the the current is anti clockwise. That doesn't make sense to me.

Is there a mistake in the answers?
 
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Your answer "clockwise" looks correct to me (assuming ##B_0## and ##\beta## are positive and assuming you're viewing from above the x-y plane.)
 
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The induced current would oppose the change: so increase B in the -z direction. This is "clockwise" looking "down" at z (axial rotation vector in -z direction). Very clumsy nomenclature.
 
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hutchphd said:
This is "clockwise" looking "down" at z (axial rotation vector in -z direction). Very clumsy nomenclature.

Besides the point, but related anyway, it did irritate me when my chemistry textbooks would just say an (+) enantiomer rotates the plane of polarisation clockwise, whilst a (-) enantiomer rotates the plane of polarisation anticlockwise. I mean, where are you viewing the beam from?!
 
And of course for the pedagogy it really didn't matter so long as you understood the existence of chirality. But agreed.
 
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