Determining the second order polynomial from the intersection points

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To determine the second order polynomial ax^2 + bx + c from the intersection points (-2, 0), (0, 2), and (1, 0), one can set up a system of equations based on these points. The equations derived from the points are: 4a - 2b + c = 0, c = 2, and a + b + c = 0. By substituting c into the first two equations, the values of a and b can be solved. Understanding the relationship between polynomial factors and roots simplifies this process significantly. This method provides a clear path to finding the polynomial's coefficients.
Cinitiator
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Homework Statement


Let's say that we have a second order polynomial function, and we know all of the points where it intersects with the x and y axis. Ex: (-2; 0), (0; 2), (1; 0)

How does on determine the ax^2+bx+c polynomial form based on that?

Homework Equations


-


The Attempt at a Solution



Tried searching for it on Google without any luck.
 
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Cinitiator said:

Homework Statement


Let's say that we have a second order polynomial function, and we know all of the points where it intersects with the x and y axis. Ex: (-2; 0), (0; 2), (1; 0)

How does on determine the ax^2+bx+c polynomial form based on that?

Homework Equations


-


The Attempt at a Solution



Tried searching for it on Google without any luck.

What is a second order polynomial? What are both coordinates of the intersections?
 
Cinitiator said:

Homework Statement


Let's say that we have a second order polynomial function, and we know all of the points where it intersects with the x and y axis. Ex: (-2; 0), (0; 2), (1; 0)

How does on determine the ax^2+bx+c polynomial form based on that?
I assume that you are saying that this is a general second order polynomial so you have answered sbj-2812's first question. You should also know that the point (a, b) lies on the graph of y= f(x) if and only if b= f(a). If (-2, 0), (0, 2), and (1, 0) are on the graph of y= ax^2+ bx+ c then we must have 0= a(-2)^2+ b(-2)+ c or 4a- 2b+ c= 0, 2= a(0)^2+ b(0)+ c or c= 2, and 0= a(1)^2+ b(1)+ c or a+ b+ c= 0
Solve the equations a+ b+ c= 0, c= 0, and 4a- 2b+ c= 0 for a, b, and c.

Homework Equations


-

The Attempt at a Solution



Tried searching for it on Google without any luck.
 
Cinitiator said:

Homework Statement


Let's say that we have a second order polynomial function, and we know all of the points where it intersects with the x and y axis. Ex: (-2; 0), (0; 2), (1; 0)

How does on determine the ax^2+bx+c polynomial form based on that?

Homework Equations


-


The Attempt at a Solution



Tried searching for it on Google without any luck.

Do you know the relation between factors of a polynomial and the roots of the polynomial? If you do not, see http://www.sosmath.com/algebra/factor/fac02/fac02.html . Using the relationship makes your problem very easy. That is material well worth knowing.

RGV
 
Cinitiator said:

Homework Statement


Let's say that we have a second order polynomial function, and we know all of the points where it intersects with the x and y axis. Ex: (-2; 0), (0; 2), (1; 0)

How does on determine the ax^2+bx+c polynomial form based on that?

Homework Equations



The Attempt at a Solution



Tried searching for it on Google without any luck.
A second order (second degree) polynomial having the form ax2+bx+c and having two real root may be written as a(x-D)(x-F).

From this it should be easy to solve your problem.
 

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