Determining the truth value of this quantified statement

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SUMMARY

The discussion centers on the truth value of the quantified statement: ∀x ∀y, ∃z such that y - z = x. The initial claim of falsehood is based on specific values of x and y, leading to a contradiction. However, the correct interpretation emphasizes that for any chosen x and y, a corresponding z can be found, confirming the statement as true. The misunderstanding arises from fixing z while varying x and y, which does not align with the logical structure of the statement.

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Homework Statement



I am trying to determine the truth value of this statement:

[tex]\forall \mbox{ }x \mbox{ and } \forall \mbox{ }y, \exists \mbox{ }z \mbox{ such that } y-z=x.[/tex]

Homework Equations



N/A

The Attempt at a Solution



Here is how I arrived at my answer of false. The textbook lists the correct answer as true.

Consider x=0 and y=1.

We have,

1-z=0.

For this statement to be true, z must be equal to 1.

Now, leaving z=1, switch to x=2 and y=0. This gives

0-1=2. (1)

Equation (1) is a false statement. Therefore, there exists no z such that for all x and for all y, y-z=x.

Where is my logic wrong?

Thanks
 
Last edited:
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Hi opticaltempest,

I believe the problem is that you're fixing z, then fixing x and y. The statement is, given some x and y, there exists z.

If you fix all three, then it's easy to find a contradiction to the statement for all x,y, z, we have y - z = x, but this isn't what your original statement said.

Hope that helps!
 

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