Device that can assist lifting a force of 700 N or greater?

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SUMMARY

Devices that assist in lifting forces of 700 Newtons (approximately 160 pounds) include screw jacks and linear actuators. Screw jacks, commonly found in car jacks, are lightweight and capable of lifting heavy loads. Linear actuators offer a customizable solution for various lifting needs, with capabilities ranging from small forces to several tons. Fluidic muscles, such as those produced by Festo, provide a fast-acting and lightweight alternative for tension-based lifting.

PREREQUISITES
  • Understanding of Newtons as a unit of force
  • Familiarity with screw jacks and their applications
  • Knowledge of linear actuators and their operational principles
  • Basic physics concepts related to force, mass, and acceleration
NEXT STEPS
  • Research the specifications and applications of linear actuators
  • Explore the design and functionality of fluidic muscles
  • Investigate the physics behind force calculations using W = m*g
  • Learn about the various types of screw jacks and their lifting capacities
USEFUL FOR

Engineers, robotics developers, and anyone interested in mechanical lifting solutions will benefit from this discussion on devices capable of assisting with significant forces.

socalfusions
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Are their any devices currently available that can assist a human in exerting a force of 700 N or greater? Exactly how much force is 700 N equivalent to?

Hydraulics are the only thing that comes to my mind, is their anything lighter? What do exoskeletons use to assist the user to lift greater weights?
 
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Hi socalfusions,
You can try screw jack(power screws) which are used to lift cars. They are probably the lightest and can lift up heavy loads like automobiles.
 
700 Newtons force is equivalent to about 71 kilograms or 160 pounds.

Bob S
 
koolraj09 said:
Hi socalfusions,
You can try screw jack(power screws) which are used to lift cars. They are probably the lightest and can lift up heavy loads like automobiles.

Thanks for the suggestion, are these the same things as your average car jack in the trunk of a car? I'm looking for a device that can rapidly assist in exerting a constant up and down force of 700 N in addition to the person being able to carry the device on them.

Bob S said:
700 Newtons force is equivalent to about 71 kilograms or 160 pounds.

Bob S

Ok great, is their any resources where I could find out how to decipher how many N is equivalent to pounds?
 
socalfusions said:
Ok great, is their any resources where I could find out how to decipher how many N is equivalent to pounds?
Try this on-line one

http://www.convertunits.com/from/Newton/to/pound

It gives 157.3662597101 pounds for 700 Newtons.

Bob S
 
Yes, these are the same things as your average car jack in the trunk of a car.
Also try and google "linear actuators"
 
Bob S said:
Try this on-line one

http://www.convertunits.com/from/Newton/to/pound

It gives 157.3662597101 pounds for 700 Newtons.

Bob S

Excellent, thank you!

koolraj09 said:
Yes, these are the same things as your average car jack in the trunk of a car.
Also try and google "linear actuators"

After some quick research on linear actuators they seemed to fit the bill of what I was looking for initially. They appear to move quite slowly, although I didn't look up every type which their appear to be quite a variety of different kinds.

Are they capable of quick motions or are they limited to slow ones? What kinds of weight can you expect them to lift, possibly up to 160+ pounds? Are they small enough to where you could carry them on yourself essentially like an exoskeleton? Are they self powered or do they require an external power source? Are they generally light in weight or quite heavy?

I appreciate the feedback :approve:
 
socalfusions said:
Are they capable of quick motions or are they limited to slow ones? What kinds of weight can you expect them to lift, possibly up to 160+ pounds? Are they small enough to where you could carry them on yourself essentially like an exoskeleton? Are they self powered or do they require an external power source? Are they generally light in weight or quite heavy?

You are asking "how long is a piece of string". There are linear actuators that produce forces of any size you want from fractions of an ounce to hundreds of tons, at a whole range of speeds.

The poiwer requirement obviously depends what you want to actuator to do. Some basic formulas are

Work = force x distance
Power = work / time
Power = force x velocity
 
AlephZero said:
You are asking "how long is a piece of string". There are linear actuators that produce forces of any size you want from fractions of an ounce to hundreds of tons, at a whole range of speeds.

The poiwer requirement obviously depends what you want to actuator to do. Some basic formulas are

Work = force x distance
Power = work / time
Power = force x velocity

I see, I wasn't aware of how broad the customization of linear actuators were. That's amazing that they can produce forces into the tons!

Are linear actuators essentially completely customizable in any shape or form considering that you have the right equipment to create them?
 
  • #10
Are you familiar with "fluidic muscles" (Festo makes some)? Though they only work in tension they are relatively fast acting and light weight.
 
  • #11
tvavanasd said:
Are you familiar with "fluidic muscles" (Festo makes some)? Though they only work in tension they are relatively fast acting and light weight.

No I've never heard of them before, I'll do some research on them they sound very interesting.
 
  • #12
socalfusions said:
Ok great, is their any resources where I could find out how to decipher how many N is equivalent to pounds?

Give a man a fish and he will eat for a day. Teach a man to fish and he will eat for a lifetime. So I'll explain to you how it's done rather than give you an online calculator.

Okay, firstly, if an object is exerting a force of 700N downwards, then its mass can easily be calculated, as W = m*g, where W = weight (in Newtons, which is described as a force in this instance), m = its mass in kilograms, and g = acceleration due to gravity, i.e. 9.81m/s/s.

Therefore rearranging the above equation to find m yields m = W/g = 700/9/81 = 71.36kg. Now, there are roughly 2.2lbs per kilogram, so multiplying this figure by 2.2 gives ~157lbs.
 

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