MHB Dice Probability (5 Sided Dice and 6 Sided Dice)

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The discussion revolves around calculating probabilities for a gambling game involving a five-faced die A and a six-faced die B. The user seeks help in determining which of three options provides the highest chance of winning. The first option involves rolling a 2 with die A and either a 2 or 4 with die B, while the second option involves rolling a 1 with die A and any number other than 1 with die B. The user is particularly stuck on the third option, which requires finding combinations of rolls that total 7. The key to solving this is identifying all possible outcomes that sum to 7 from the rolls of both dice.
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hi I am stuck on a question and was wondering if anyone could help me out (show a working solution/steps) to the problem.

here's the question:

Las Vegas Casino has introduced a new gambling game. A five-faced die A has numbers 1, 2, 2, 2
and 5 on its faces. This die and a normal die B (i.e. one with the numbers 1 to 6 on its six faces) are
rolled together. Which of the following choices offers you the highest chance of winning? a. Rolling a 2 with A and either a 2 or 4 with B? = My answer: 3/5 x 2/6 = 1/5b. Rolling a 1 with A and any number other than a 1 with B? My answer: 1/5 x 5/6 = 1/6c. Rolling two numbers on A and B such that their total is 7? This is the one I am stuck on! and therefore do not know which option offers you the highest chance of winning. In each case, if you win, what is the probability that you rolled a 2 with die B? Also, this question too!

Many Thanks
 
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For question $c$ you have to ask yourself: how many possible outcomes are there to make a sum of $7$? In other words, how many combinations $a+b = 7$ are possible where $a$ is a number generated by rolling die A and $b$ a number generated by rolling die B. For example you could have $2$ and $5$ or $1$ and $6$ etc...
 

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