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Did Fubini's Theorem fail here?
Fubini's Theorem did not fail in the discussed case because the necessary conditions for its application were not met. Specifically, the function f:[0,1]^2→[-∞,+∞] must either be non-negative for all x, y in [0,1] or the integral of the absolute value of f over the square [0,1]^2 must be finite. In this instance, neither of these conditions was satisfied, confirming that Fubini's Theorem is applicable only under strict criteria.
PREREQUISITESMathematicians, students of real analysis, and anyone studying integration techniques in calculus will benefit from this discussion.