Did I Calculate the Positron's Momentum Correctly in Pion Decay?

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SUMMARY

The discussion focuses on calculating the momentum of the positron in the decay process of a pion, specifically the decay π+ → e+ + ve. The user correctly applies the principles of conservation of momentum and energy, starting with the pion at rest, leading to the conclusion that the momentum of the positron is -69.799 MeV/c. The calculations utilize the mass-energy equivalence formula E = mc² and the relationship for massless particles, confirming the positron's momentum through a series of substitutions and simplifications.

PREREQUISITES
  • Understanding of particle physics, specifically pion decay processes.
  • Familiarity with conservation laws in physics, particularly conservation of momentum and energy.
  • Knowledge of relativistic energy-momentum relations, including E² = (pc)² + (mc)².
  • Basic understanding of mass-energy equivalence, E = mc².
NEXT STEPS
  • Study the implications of conservation laws in particle decay scenarios.
  • Learn more about the properties of neutrinos and their role in particle interactions.
  • Explore advanced topics in relativistic kinematics and momentum calculations.
  • Investigate experimental methods for measuring particle momenta in decay processes.
USEFUL FOR

This discussion is beneficial for physics students, particle physicists, and anyone interested in the mechanics of particle decay and momentum calculations in high-energy physics.

lee_sarah76
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Homework Statement



We are the given the rare decay:

π+ → e+ + ve

Also, we are given mπ = 139.6 MeV/c2, mv ≈ 0, me+ = 0.511 MeV/c2

And we are given that the decay starts with the pion at rest, so I took that to mean that pπ = 0

Solve for the momentum of the positron.

Homework Equations



Conservation of Momentum
Conservation of Energy
E2 = (pc)2 + (mc)2
E = mc2

The Attempt at a Solution



I started with the fact that since the pion was at rest before decay, pπ = 0 so pe + pv = 0.

Then, also using the fact that the pion was at rest before decay I solved for its energy using the formula E = mc2, substituting mπ = 139.6 MeV/c2 getting that Ebefore = 139.6 MeV.

Ebefore = Eafter = Ee + Ev

(Ee)2 = (pec)2 + (mec2)2

And because the neutrino is massless:
Ev = pv*c

From before, since Ee + Ev = 139.6 MeV, I solved for Ee to get Ee =139.6 MeV - Ev.

Then I substituted pvc for Ev to get the equation:

(139.6 MeV - pvc)2 = (pec)2 + (mec2)2

The (pc)2 would cancel each other out, leaving:

-279.2pvc = -19487.8 MeV

So, pv = 69.799 MeV/c leaving pe = -69.799 MeV/c

My question is, is this right, or have I made some glaring mistakes in my method?
 
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