1. The problem statement, all variables and given/known data A possible decay mode a of a positive Kaon in the production of three Pions as shown below:. K+ → π+ + π+ + π− Whats is the maximum Kinetic energy that any one of the pions can have? The kaon is a rest when it decays and so its momentum is 0. 2. Relevant equations p(π+)=p(π−)=p E(k)=E(π+) + E(π+) + E(π−) Where E=√((pc)^2+(mc^2 )^2 ) (E^2)-(p)^2=(m)^2 3. The attempt at a solution The mass of the koan:493.7Mev/c^2 The mass of a Pion: 139.6 Mev/c^2 AS The mass of the three Pions is the same the expression for the total energy becomes: 3(√((pc)^2+(mpionc^2 )^2 )=mkaonc2 and through rearranging I come up with a momentum of 80.2MeV. Alternatively I tried to use the following approach: E(pion)=1/3*(Ek)=164.7MeV P=164.7Mev-139.6MeV=25.1Mev However the book from which the question is taken from (Particle Physics By Anwar Kama: problem 3.19) gives the solution as 50Mev? Any help on this would be greatly appreciated as it is driving me nuts trying to figure it out.