Did I do this physics problem right?

  • Thread starter zeromodz
  • Start date
  • #1
245
0
Its not for homework, I just want to make sure I can do this.

What is the value of the coefficient of friction between the box and the floor?
A man pushes a box with a mass of 10kg at a constant velocity across the floor. he pushes with a constant force of 25N. What is the coefficient of friction value?


F = ukN
uk = F / N
uk = (25) / ((10)(9.8))
uk = 0.25
 

Answers and Replies

  • #2
You will need to know at what rate the box accelerates at in order to find the friction co-efficient.
 
  • #3
208
1
You will need to know at what rate the box accelerates at in order to find the friction co-efficient.
Not for this problem. If the velocity is constant, which the problem stated, then the net force is zero.

So mgcosθμ = 25

98μ = 25

μ = .2551...

so yes you're correct.
 

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