- #1

bgt

A 10.0 kg box rest on a horizontal board. One end of the board is slowly raised to 12.8° with the floor, the box slides at a constant velocity. (Use this information to find the kinetic coefficient). Find the magnitude and direction of the acceleration of the box when the board is raised to an angle of 13.9° with the floor.

2.35m/s^2 being acceleration (=(gravity)sin).

**2.**I am absolutely STUCK at finding the coefficient for kinetic force, especially with the given information.**3.**mg⋅cos12.8-10kg⋅2.35m/s^2 divided by 98N (mg)2.35m/s^2 being acceleration (=(gravity)sin).

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