Did I understand sound refraction (am I doing it right)?

[Amar]

Homework Statement

Moving through air, a wave hits a steady area of water with a angle of 13°. The velocity of the wave in air is 550 m/s and in the water 1650 m/s. What is the refraction angle of the wave? Does the angle move away or to the line of symmetry?
Btw. I think I translated it correctly from Bosnian so correct me if it's wrong

Homework Equations

So I didn't understand it so I went looking on the internet and found out it has to do something with some Huygenss dude.
Anyway this is what I went with :
sinα/sinβ = c₁/c₂

The Attempt at a Solution

What I got was β = 41°(nearly)
and the wave goes away from the line of symmetry

 

[gneill]

Homework Statement

Moving through air, a wave hits a steady area of water with a angle of 13°. The velocity of the wave in air is 550 m/s and in the water 1650 m/s. What is the refraction angle of the wave? Does the angle move away or to the line of symmetry?
Btw. I think I translated it correctly from Bosnian so correct me if it's wrong

The translation is okay as far as it goes, but a couple of points need clarification: First, what is the 13° angle measured with respect to? Second, what is the "line of symmetry"? Is it the normal (perpendicular) to the interface between the two media?

Homework Equations

So I didn't understand it so I went looking on the internet and found out it has to do something with some Huygenss dude.

You should also have come across Snell and Descartes.

Anyway this is what I went with :
sinα/sinβ = c₁/c₂
3. The Attempt at a Solution
What I got was β = 41°(nearly)
and the wave goes away from the line of symmetry

Maybe you should keep a few more decimal places in your intermediate calculations; I get a value that is just a little bit larger than that assuming that the angles are measured with respect to the normal.

 

[Amar]

First, what is the 13° angle measured with respect to? Second, what is the "line of symmetry"? Is it the normal (perpendicular) to the interface between the two media?

Thanks for pointing that out. Yes the 'line of symmetry' should be the normal to the interface ( it's actually called that in my language but I didn't think it would apply to English too). And the angle is closed by the interface and normal.

Maybe you should keep a few more decimal places in your intermediate calculations; I get a value that is just a little bit larger than that assuming that the angles are measured with respect to the normal.

So I'm guessing that my attempt was correct. My result was 41°17'59,54'' and that's just a bit larger :D
Thanks for the reply :)
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