Did photon obey Uncertainity Principle?

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Photon has no mass.So when we apply Uncertainity principle to photon
position*velocity*mass=greater than plancks constant
So when we use mass as null,the equation implies that 0<h.
That is h is negative.But h is positive.
Please explain me this.
 
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The uncertainty relation follows from the commutation relation of the momentum and position operators. The photon does not carry a mass, but it does carry a momentum.
 
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velocity*mass
This is not momentum. This is an approximation of momentum at low velocity. The correct dispersion relations for the massless particles as the photon is
[itex]E=pc=\hbar\omega=\hbar c k[/itex]
 
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ZapperZ

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Photon has no mass.So when we apply Uncertainity principle to photon
position*velocity*mass=greater than plancks constant
So when we use mass as null,the equation implies that 0<h.
That is h is negative.But h is positive.
Please explain me this.
The single-slit diffraction phenomenon is the clearest example of photons "obeying" the HUP.

Zz.
 
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Thank you
 
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As far as we know, everything obeys quantum principles...including HUP...
 
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Thanks a lot
 

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