Dielectric boundary value problems

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In solving dielectric boundary value problems, the introduction of an image charge in the z<0 region is necessary to accurately represent the electric potential. The image charge, while located at the same position as the original charge, has a different value, denoted as ##q''##, which is determined through analysis. The potential ##\phi_1## is calculated under the assumption that the dielectric material ##\varepsilon_1## extends throughout all space, affecting the image charge in the z>0 region. Similarly, the potential ##\phi_2## is derived with the assumption that the yellow dielectric ##\varepsilon_2## also permeates all space. This approach ensures a comprehensive understanding of the electric field behavior across the dielectric boundaries.
lys04
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Homework Statement
Why in this problem when solving for the electric potential in the z<0 region we introduce another image charge that is the same as the original charge instead of just using the original charge? I don't really get the explanation they provide.
Relevant Equations
$$\vec{D}=\epsilon \vec{E}$$
1745389441297.png

1745389455722.png
 
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Hard to read.
The text should be fixed. It is not clear.
 
lys04 said:
Homework Statement: Why in this problem when solving for the electric potential in the z<0 region we introduce another image charge that is the same as the original charge instead of just using the original charge?
When finding the potential ##\phi_1## in region z<0, the image charge is not the same as the original charge. The image charge has the same location as the original charge, but the charge of the image is ##q''##, which differs from the original charge ##q##. The value of ##q''## will be determined in the analysis.

Also, when writing the potential ##\phi_1##, we imagine that the purple dielectric ##\varepsilon_1## extends throughout all of space: both z < 0 and z > 0. Thus, although ##q''## is located in the region ##z > 0##, ##q''## is taken to be immersed in dielectric material with ##\varepsilon_1##.
That's why you see this figure
1745430570324.png


Likewise, in writing the potential for ##\phi_2##, the yellow dielectric ##\varepsilon_2## is assumed to extend throughout all of space.
1745430531692.png
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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