# Dielectric Compacitors Confirmation

1. Sep 10, 2008

### Trenthan

Dielectric compacitors can contain 1 or multiple dielectrics, if we say have a capacitor with 3 dielectrics between the two plates. We can model it as 3 capacitors in series. Since we know that Capacitors in series the equivalent is

(1/Ceq) = (1/C1)+(1/C2)+(1/C3)

Wouldnt the overall capacitance be lower by having 3 dielectric between the two plates. If we separated the 3 into 3 seprate dielectric capacitors wouldnt the charge across all 3 remain constant Q0=Q1=Q2=Q3.

Therefore the potential for each capacitor depends only on the width of the dielectric since
Vcap#1-3=Ed=(Q/Ae0)*d

Since A is constant all the same size, e0= 8.85*10-12, and Q is constant since they are in series. The potential depends only on "d" the width of the dielectric, thus capacitance C=Ae0/d, also only depends on the "d".

Basically what im trying to say is if we have 3 individual capacitors, than arrange them in series the capacitance islower. Therefore if we want to build a capacitor with a high capacitance we only use a single dielectric since multiples decrease the capacitance of the capacitor due to the series arrangement of dielectric in the capacitor.

Hope this is clear thanks Trent

2. Sep 10, 2008