Find Dielectric Constant from Parallel Plate Capacitor Problem

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SUMMARY

The discussion centers on calculating the dielectric constant of a parallel plate capacitor with a capacitance of 1.5µF and an initial voltage of 12V. After removing the battery and inserting a dielectric, the measured voltage drops to 5.0V. The relevant equation is Q=CV, where Q represents charge, C is capacitance, and V is voltage. By comparing the initial and new capacitances, one can derive the dielectric constant of the material inserted between the plates.

PREREQUISITES
  • Understanding of capacitor fundamentals, including capacitance and voltage relationships.
  • Familiarity with the equation Q=CV for capacitors.
  • Knowledge of how dielectrics affect capacitance in parallel plate capacitors.
  • Basic algebra skills for manipulating equations and solving for unknowns.
NEXT STEPS
  • Study the impact of dielectrics on capacitance in parallel plate capacitors.
  • Learn how to derive the formula for dielectric constant from capacitance values.
  • Explore practical applications of dielectric materials in electrical engineering.
  • Review related equations for capacitors, including energy stored and charge relationships.
USEFUL FOR

Students in physics or electrical engineering, educators teaching capacitor theory, and anyone interested in understanding the effects of dielectrics on capacitor performance.

JordanHood
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Homework Statement


A parallel plate capacitor has a capacitance of 1.5µF with air between the plates. The capacitor is connected a 12V battery and charged. The battery is then removed. When a dielectric is placed between the plates, a potential difference of 5.0V is measured across the plates. What is the dielectric constant of the material?

Homework Equations

The Attempt at a Solution


I know that Q=CV. however this is the only equation I find relevant as all the other equations I know for finding the dielectric constant involve area and distance between the plates. Can someone just help me get started with this question?
 
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Inserting a dielectric will increase the capacitance but charge on the the plates will be same. Can you write an equation with this information and find the new capacitance? Comparing the two capacitances, you can calculate the dielectric constant of the new capacitor.
 

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