Diferent kind of energy (heat and kinetic)

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Discussion Overview

The discussion revolves around the differences between heat energy and kinetic energy, particularly in the context of a hypothetical scenario involving a 1Kg iron ball heated by a chemical source versus one accelerated in space. Participants explore the implications of energy loss, measurement, and the nature of energy in different reference frames.

Discussion Character

  • Exploratory
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • Some participants propose that heat energy "sticks" to the heated ball as its temperature remains consistent across reference frames, while kinetic energy does not due to its dependence on the observer's frame of reference.
  • Others argue that the heated ball will radiate energy into space, leading to a loss of thermal energy unless it reaches thermal equilibrium with its surroundings.
  • There is a suggestion that kinetic energy remains with the moving ball as long as it does not interact with other objects, implying a difference in how these energies are retained or lost.
  • Some participants challenge the notion that heat does not have a mechanical origin, suggesting that heat can arise from mechanical motion through molecular collisions.
  • Concerns are raised about the definition of a cold reservoir and the conditions under which the heated ball loses energy, particularly in the context of space as a medium.
  • Questions are posed regarding the fundamental differences in behavior between thermal and kinetic energy, with some participants wondering if this is an unresolved question in physics.

Areas of Agreement / Disagreement

Participants express differing views on the nature of heat and kinetic energy, with no consensus reached on the fundamental differences between them or the implications of their behaviors in various contexts.

Contextual Notes

Limitations include the dependence on definitions of energy types, the role of reference frames in measurement, and the unresolved nature of certain claims regarding the origins and behaviors of heat and kinetic energy.

AlexB2010
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I have a hypothetical question:
Suppose a use a chemical source of energy to heat a 1Kg Iron ball, or, transform that same chemical energy in kinetic energy to accelerate an equal ball in space.
The heated ball in space will cool down, loosing energy.
The accelerated ball will maintain its velocity and the energy given to then will “stick” to the ball, manteining the energy level.
What is the difference in the energy that makes than stick or run away from the ball?
Thanks in advance.

Alex
 
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There is another way to look at this in which heat "sticks" but the kinetic energy doesn't.

The heating of the ball will increase its temperature. That temperature will be the same as measured by observers in other reference frames (ie. moving with respect to the ball). So, in that sense, the thermal energy sticks to the heated ball.

The kinetic energy of the moving ball will not be the same for other moving observers. For some, the kinetic energy will decrease (ie. the impulse slows it down) and for others it will increase. So kinetic energy of the "moving" ball does not "stick" to it. It depends on who is doing the measuring.

Measurement of kinetic energy is relative to the frame of reference of the observer. Measurement of temperature (molecular kinetic energy) is always related to the frame of reference of the object whose temperature is being measured.

The reason the temperature of the ball drops is: radiation. The molecules of the ball are continually accelerating and decelerating randomly. This results in emission of electromagnetic radiation. The ball will radiate energy at a rate that depends on its temperature. The ball's temperature will drop until the rate of radiation emitted is equal to the rate of radiation absorbed from other sources.

The "moving" ball does not radiate because its motion is uniform.

AM
 
Hi Andrew,
I don’t think the changing of reference can be used here, because since Galileo, to perform a physics experiment you need to determine a reference frame were the measurements are made. On the same frame of reference the accelerated ball will maintain their velocity and the energy given to then will increase the “energy level” of the ball.
On heat, I know that they will be loose in space equilibrating in their environment, irradiating in space, but since you point out relativity: Heat is considered kinetic energy of individual molecules, why they will be the same on all frames of reference? Since they are movement like any other.
My question is, why the difference behavior of a energy that came from the same source? Why kinetic energy not irradiate in space? Why the molecular motion is different from acceleration on the whole ball?
Thanks,
Alex
 
AlexB2010 said:
I have a hypothetical question:
Suppose a use a chemical source of energy to heat a 1Kg Iron ball, or, transform that same chemical energy in kinetic energy to accelerate an equal ball in space.
The heated ball in space will cool down, loosing energy.
The accelerated ball will maintain its velocity and the energy given to then will “stick” to the ball, manteining the energy level.
What is the difference in the energy that makes than stick or run away from the ball?
Thanks in advance.

Alex

Well, you need to be a little careful here- the moving ball will continue to move as long as it doesn't interact with anything else, and the heated ball will radiate only if it is allowed to interact with a cold reservior.

But using common sense, you are basically correct; heat and kinetic energy are two different kinds of energy, and can be interconverted to some degree. Heat can be converted into work, and work can be converted into heat... not with 100% efficiency, but that's entropy for you...
 
Hi Andy, thanks again.
Somehow kinetic energy becomes part of a moving body and heat goes away. Someone know how? What happens in a small particle defined by their momentum if they receive kinetic energy.

Alex
 
Andy Resnick said:
Well, you need to be a little careful here- the moving ball will continue to move as long as it doesn't interact with anything else, and the heated ball will radiate only if it is allowed to interact with a cold reservior.
This requires a bit of clarification. I would not consider space to be a cold reservoir. But the heated ball will radiate heat into space at a rate that is only dependent on its temperature. The ball will lose thermal energy unless and until the rate of absorption of energy from other sources equals or exceeds the rate at which it loses thermal energy. But it always radiates.

But using common sense, you are basically correct; heat and kinetic energy are two different kinds of energy, and can be interconverted to some degree. Heat can be converted into work, and work can be converted into heat... not with 100% efficiency, but that's entropy for you...
One might want to phrase this a little differently. Heat and mechanical energy derive from kinetic energy of matter. Heat is the kinetic energy of random molecular (non-uniform) motion. Mechanical energy is the kinetic energy of uniform, non-random motion of macroscopic pieces of matter.

AM
 
Andrew Mason said:
This requires a bit of clarification. I would not consider space to be a cold reservoir. But the heated ball will radiate heat into space at a rate that is only dependent on its temperature. The ball will lose thermal energy unless and until the rate of absorption of energy from other sources equals or exceeds the rate at which it loses thermal energy. But it always radiates.

One might want to phrase this a little differently. Heat and mechanical energy derive from kinetic energy of matter. Heat is the kinetic energy of random molecular (non-uniform) motion. Mechanical energy is the kinetic energy of uniform, non-random motion of macroscopic pieces of matter.

AM

The heated ball will not lose heat energy if it is at the same temperature as it's surroundings.

Heat does not have a mechanical origin.
 
Andy Resnick said:
The heated ball will not lose heat energy if it is at the same temperature as it's surroundings.
Can the surroundings not be empty space? The temperature of a vacuum is undefined, since there are no molecules in a vacuum. But a heated ball in space can still lose heat energy.
Heat does not have a mechanical origin.
I would have to disagree. Heat can originate from mechanical motion. The flow of heat is essentially a mechanical flow - molecules transferring kinetic energy to other molecules through physical collisions.

AM
 
Andrew Mason said:
.I would have to disagree. Heat can originate from mechanical motion. The flow of heat is essentially a mechanical flow - molecules transferring kinetic energy to other molecules through physical collisions.

AM

This discussion has been had numerous times on other threads; I have no desire to cover that ground again unless you have something original to say. I'll simply mention the following:

1) You would agree (hopefully) that electromagnetic energy does not have a mechanical origin; why insist that thermal energy have a mechanical origin?

2) Your statement only has meaning in the context of equilibrium/partition functions/statistical considerations. Dissipative process (e.g. friction, viscous losses) are exempt from these considerations. There is no (AFAIK) mechanical microscopic model for friction. Do you know of one?

As to your first comment, blackbody radiation has a well-defined temperature and requires no atoms. Put the ball in a cavity held at the same temperature, and it cannot lose energy to the surroundings.
 
  • #10
Coming to the basic question again:
Thermal energy given or taken to a body will equilibrate on their surroundings. Kinetic energy that accelerates the body will stay glued to de body.
Why this happens? Why differences, since both energy are movement?
Answers exist? or is this an unsolved question to physics?

Alex
 
  • #11
AlexB2010,

As I mentioned earleir, kinetic energy does not 'stay glued' to the body, if the body can interact with another body (e.g. friction). Heat will not 'stay glued' to the body either, if it can interact with other bodies (e.g. thermal equilibration).
 
  • #12
Andy Resnick said:
AlexB2010,

As I mentioned earleir, kinetic energy does not 'stay glued' to the body, if the body can interact with another body (e.g. friction). Heat will not 'stay glued' to the body either, if it can interact with other bodies (e.g. thermal equilibration).

Hi Andy,
I do a little thinking based in your explanation; correct me if I am wrong.
In my think experiment, in releasing the chemical bonds I liberate thermal energy that are used to heat a ball or run some kind of machinery that will convert thermal energy to motion that will be applied to the ball given acceleration and increasing the speed.
The ball traveling in open space in uniform motion will not interact with other solids and then will go forever.
The heated ball have the internal molecular motion increased, the molecules will be given kinetic energy. The internal collisions will transform the kinetic energy in thermal radiation that is capable of moving in free space, making the ball loose energy (In colder space).
Since the accelerated ball don’t have increased molecular motion, the kinetic energy given to then will be all in one direction, molecular interaction don’t occur and the kinetic energy will stay in the ball as long they are in uniform motion.
Thermal energy will be defined as wave of amplitude and frequency defined; can I define kinetic energy the same manner?
What happens if I give kinetic energy to a photon?

Alex
 
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  • #13
Andy Resnick said:
1) You would agree (hopefully) that electromagnetic energy does not have a mechanical origin; why insist that thermal energy have a mechanical origin?
I am not insisting that thermal energy must have a mechanical origin. I am just disagreeing with your general statement that thermal energy (heat) does not have a mechanical origin.

2) Your statement only has meaning in the context of equilibrium/partition functions/statistical considerations. Dissipative process (e.g. friction, viscous losses) are exempt from these considerations. There is no (AFAIK) mechanical microscopic model for friction. Do you know of one?
I agree that friction is necessarily a macroscopic phenomenon. All collisions at the molecular level are elastic.

As to your first comment, blackbody radiation has a well-defined temperature and requires no atoms. Put the ball in a cavity held at the same temperature, and it cannot lose energy to the surroundings.
The black-body consists of matter in some form (plasma, atoms) and has a temperature. But the radiation does not really have a temperature. We refer to radiation temperature but what we are really referring to is the temperature of the blackbody matter that produces the observed electro-magnetic spectrum.

AM
 
  • #14
AlexB2010 said:
What happens if I give kinetic energy to a photon?
Kinetic energy is defined only for bodies of matter. You can't do work on a photon. You can't change its speed so you can't give it kinetic energy. It does have momentum, though.

AM
 
  • #15
Andrew Mason said:
Kinetic energy is defined only for bodies of matter. You can't do work on a photon. You can't change its speed so you can't give it kinetic energy. It does have momentum, though.

AM

The ability of receive kinetic energy, is it exclusive to fermions ?
 
  • #16
Andrew Mason said:
But the radiation does not really have a temperature. We refer to radiation temperature but what we are really referring to is the temperature of the blackbody matter that produces the observed electro-magnetic spectrum.

AM

Well.. this *is* an original statement. It's also at variance with Planck's law. No, blackbody radiation is the spectral distribution of a free field (with infinite degrees of freedom) at thermal equilibrium with a reservior. It is material independent, especially since there's no such thing as 'black body matter'.
 
  • #17
Andy Resnick said:
Well.. this *is* an original statement. It's also at variance with Planck's law. No, blackbody radiation is the spectral distribution of a free field (with infinite degrees of freedom) at thermal equilibrium with a reservior.
You are misinterpreting what I said. My point was that only matter can really have a temperature, at least in the classical sense of temperature. Radiation temperature is assigned to a spectrum of radiation that is emitted by a blackbody. The radiation temperature is the surface temperature of the blackbody that would produce that radiation distribution. That is all I am saying. If I am wrong on that, please correct me.
It is material independent, especially since there's no such thing as 'black body matter'.
My reference to "the blackbody matter" is to the matter that makes up the blackbody. A blackbody has to be made up of matter. It doesn't matter what the matter is. Radiation can only be emitted from matter. If I am wrong on that, please correct me.

We seem to be getting a little far from the original question here.

AM
 
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  • #18
Andrew Mason said:
You are misinterpreting what I said. My point was that only matter can really have a temperature, at least in the classical sense of temperature. Radiation temperature is assigned to a spectrum of radiation that is emitted by a blackbody. The radiation temperature is the surface temperature of the blackbody that would produce that radiation distribution. That is all I am saying. If I am wrong on that, please correct me.
My reference to "the blackbody matter" is to the matter that makes up the blackbody. A blackbody has to be made up of matter. It doesn't matter what the matter is. Radiation can only be emitted from matter. If I am wrong on that, please correct me.

We seem to be getting a little far from the original question here.

AM

I'm just following where you are leading.

Edit: Let me try a different track, and describe blackbody radiation.

It is true that blackbody radiation can be defined as "the electromagnetic radiation emitted by a blackbody object at temperature 'T'". But since a blackbody is defined as a material for which the emissivity 'e'= 1 for all wavelengths, and since no real matter has that property, it's not a particular useful way to define blackbody radiation.

A better way to construct a blackbody is to instead realize that e = 1 also means the absorptivity 'a' = 1. That's Kirchoff's law. We *can* construct an object that absorbs all wavelengths equally (and perfectly): a cavity containing a tiny hole. In fact, making the hole not tiny doesn't really affect things too much:

http://physics.nist.gov/Divisions/Div844/facilities/pyro/pyro.html
http://www.hgh.fr/corps-noir-infrarouge-infrared-source-blackbody-en.php
http://www.npl.co.uk/engineering-measurements/thermal/temperature/products-and-services/npl-fixed-point-blackbody-sources

The important thing to realize is that, by making the blackbody a *cavity* instead of an object, we have explicity demonstrated that the radiation field *itself* has a temperature, independent of the material that comprises the walls of the cavity.

Blackbody radiation has nothing to do with the matter that 'created' it.

Matter is not needed for thermal energy to exist. Thermal energy is not mechanical in origin. We can, under some conditions, *model* thermal energy in terms of molecular motion.
 
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  • #19
Andy Resnick said:
I'm just following where you are leading.

Blackbody radiation has nothing to do with the matter that 'created' it.

Matter is not needed for thermal energy to exist. Thermal energy is not mechanical in origin. We can, under some conditions, *model* thermal energy in terms of molecular motion.

Thermal energy can interact with matter generating kinetic molecular motion. How these interactions happen?

Alex
 
  • #20
Perhaps it can help to think of this as follows. Picture the ball as consisting of atoms. Indeed, everything consists of elementary particles. These elementary particles interact with each other according to certain laws of physics. In principle this allows you to describe how the ball will move, cool down etc. etc.

But this is not a very practical way of doing computations. You don't want to account for what every atom in the ball is doing when you want to compute how fast it is moving. So, wat you do is you split the motion of the ball in two parts. One part is the center of mass motion of the ball, the other part is the motion of the atoms relative to the center of mass motion. And then you describe the latter in a statistical way.

Now, we can describe the motion of the ball using conservation of energy and momentum. But because momentum is linear in the velocity, the total momentum of the system equals the momentum of the center of mass of the ball. In case of energy this is not the case. First the atoms can have potential energy, but even the sum of the kinetic energies of the atoms is not the kinetic energy of the center of mass.

This means that the statistical description you get when you average out what the atoms are doing will have to take into account the energy of the atoms. Changes in this part of the energy is what we call heat.
 
  • #21
Count Iblis said:
Perhaps it can help to think of this as follows. Picture the ball as consisting of atoms. Indeed, everything consists of elementary particles. These elementary particles interact with each other according to certain laws of physics. In principle this allows you to describe how the ball will move, cool down etc. etc.

But this is not a very practical way of doing computations. You don't want to account for what every atom in the ball is doing when you want to compute how fast it is moving. So, wat you do is you split the motion of the ball in two parts. One part is the center of mass motion of the ball, the other part is the motion of the atoms relative to the center of mass motion. And then you describe the latter in a statistical way.

Now, we can describe the motion of the ball using conservation of energy and momentum. But because momentum is linear in the velocity, the total momentum of the system equals the momentum of the center of mass of the ball. In case of energy this is not the case. First the atoms can have potential energy, but even the sum of the kinetic energies of the atoms is not the kinetic energy of the center of mass.

This means that the statistical description you get when you average out what the atoms are doing will have to take into account the energy of the atoms. Changes in this part of the energy is what we call heat.

Very nice explanation. How internal motion will became thermal radiation and equilibrates in their surroundings?
 
  • #22
AlexB2010 said:
Thermal energy can interact with matter generating kinetic molecular motion. How these interactions happen?

Alex

An excellent question, except that many more phenomena are possible than simple changes to motion. Consider the flow of heat during a phase change: evaporation, or sublimation, or more general phase changes like the glass transition. Thermal energy can change viscosity, density, or optical properties of matter as well.

A useful way to model these interactions is by phenomenological constitutive relations; for example the heat capacity and the latent heat, which you may be familiar with, but things like thermo optic coefficients as well:

http://www.sciencedirect.com/science?_ob=ArticleURL&_udi=B6TXW-4K3D36B-8&_user=10&_coverDate=06%2F28%2F2006&_rdoc=1&_fmt=high&_orig=search&_sort=d&_docanchor=&view=c&_searchStrId=1368350345&_rerunOrigin=google&_acct=C000050221&_version=1&_urlVersion=0&_userid=10&md5=6fc247327a61c5bd41edf757b0ab3a9a

By going over to a mechanical-only theory (statistical mechanics is a *mechanical* theory), some information is gained: the modeling of heat as motion. However, much more information is lost: the origin of dissipation, for example. Statistical mechanics is totally inappropriate (and unable) to discuss this:

http://www.google.com/url?sa=t&sour...q3iaYL&usg=AFQjCNEYgNrfANj8Mip5H7RgeNgk-NbI4A
 
  • #23
Statistical mechanics is totally inappropriate (and unable) to discuss this


That's nonsense. Statistical mechanics is the fundamental basis of all of thermal physics. The very concept of dissipation can only be properly formulated within a statistical theory. Very general theorems like the fluctuation-dissipation theorem, Onsager relations, Green-Kubo relations etc. etc. can be derived using statistical mechanics methods.
 
  • #24
AlexB2010 said:
Very nice explanation. How internal motion will became thermal radiation and equilibrates in their surroundings?

This is a manifestation of the second law of thermodynamics. It is a consequence of the fact that all accessible states of a system are a priori equally likely. This is just like throwing dice, the numbers 1 to 6 are all eqally likely. It is the same with the huge number of microstates of a system.

Now when you throw two dice and you add up te numbers you will see that the total of 7 is ore likely, because there are mnore states that corresond to a sum of 7 than there are for, say, 2.

Similarly, energy is dissipated as a consequence of the number of possible states increasing in a certain direction. i.e. when the energy ids competely dissipated, there are far more states the whole system (the ball plus environment in this case) can be in than in the original state. The logarithm of te number of states is called entropy; the second law says that the total entropy can only increase.
 
  • #25
Andy Resnick said:
An excellent question, except that many more phenomena are possible than simple changes to motion. Consider the flow of heat during a phase change: evaporation, or sublimation, or more general phase changes like the glass transition. Thermal energy can change viscosity, density, or optical properties of matter as well.

A useful way to model these interactions is by phenomenological constitutive relations; for example the heat capacity and the latent heat, which you may be familiar with, but things like thermo optic coefficients as well:

http://www.sciencedirect.com/science?_ob=ArticleURL&_udi=B6TXW-4K3D36B-8&_user=10&_coverDate=06%2F28%2F2006&_rdoc=1&_fmt=high&_orig=search&_sort=d&_docanchor=&view=c&_searchStrId=1368350345&_rerunOrigin=google&_acct=C000050221&_version=1&_urlVersion=0&_userid=10&md5=6fc247327a61c5bd41edf757b0ab3a9a

By going over to a mechanical-only theory (statistical mechanics is a *mechanical* theory), some information is gained: the modeling of heat as motion. However, much more information is lost: the origin of dissipation, for example. Statistical mechanics is totally inappropriate (and unable) to discuss this:

http://www.google.com/url?sa=t&sour...q3iaYL&usg=AFQjCNEYgNrfANj8Mip5H7RgeNgk-NbI4A

In my simple thinking, matter has some properties that make molecules liking to be together. The likeness to be together will depend on atomic properties of molecule, on the think experiment I just use pure Iron because is a simple chemical element and all molecules will share the same properties. Increasing heat will make molecules move and being able to counteract that's properties, passing some point and the solid will be liquid and another point vapor.
In complex materials like the ones that you show, will be an increased complexity of states since there are more diverse chemical bonds changing the basic behavior of molecules.
But my question is very simple. How thermal radiation increases kinetic motion of molecules? How this waves interact to generate molecular motion?
 
  • #26
Count Iblis said:
This is a manifestation of the second law of thermodynamics. It is a consequence of the fact that all accessible states of a system are a priori equally likely. This is just like throwing dice, the numbers 1 to 6 are all eqally likely. It is the same with the huge number of microstates of a system.

Now when you throw two dice and you add up te numbers you will see that the total of 7 is ore likely, because there are mnore states that corresond to a sum of 7 than there are for, say, 2.

Similarly, energy is dissipated as a consequence of the number of possible states increasing in a certain direction. i.e. when the energy ids competely dissipated, there are far more states the whole system (the ball plus environment in this case) can be in than in the original state. The logarithm of te number of states is called entropy; the second law says that the total entropy can only increase.

In giving energy to a molecule I know that the electronic energy levels will increase, making some electrons jump from their orbit, did is this electronic jumps that are responsible to increased molecular motion? The heat wave will increase energy level of electrons making then jump from one state to another.
 
  • #27
AlexB2010 said:
In my simple thinking, matter has some properties that make molecules liking to be together. The likeness to be together will depend on atomic properties of molecule, on the think experiment I just use pure Iron because is a simple chemical element and all molecules will share the same properties. Increasing heat will make molecules move and being able to counteract that's properties, passing some point and the solid will be liquid and another point vapor.
In complex materials like the ones that you show, will be an increased complexity of states since there are more diverse chemical bonds changing the basic behavior of molecules.
But my question is very simple. How thermal radiation increases kinetic motion of molecules? How this waves interact to generate molecular motion?

My problem is that you have thrown all all the relevant issues in order to create an overly simplified model. Even so- your too-simple model will predict the wrong behavior for liquid water between 0 and 4 deg. C. How can you modify your simple model to account for the anomalous thermal expansion of water?
 
  • #28
Andy Resnick said:
My problem is that you have thrown all all the relevant issues in order to create an overly simplified model. Even so- your too-simple model will predict the wrong behavior for liquid water between 0 and 4 deg. C. How can you modify your simple model to account for the anomalous thermal expansion of water?

I am just trying to figure out some basic principles and avoiding complicating when is not really necessary. If I am guessing right this anomalous water expansion will be due to crystalline arrangement of water molecules.
 
  • #29
AlexB2010 said:
I am just trying to figure out some basic principles and avoiding complicating when is not really necessary. If I am guessing right this anomalous water expansion will be due to crystalline arrangement of water molecules.

Guessing is not science. What is your evidence?
 
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  • #30
Andy Resnick said:
Guessing is not science. What is your evidence?

You are right guessing is only part of science, first you need to see a phenomena, after you make educated guesses (hypothesis), after you experimentally test your guesses and if everything goes well make a theory or go back to phase 2, guessing.

Water isn’t a simple molecule because they are made of two different substances, and do not share the properties with neither, oxygen or hydrogen. The two hydrogen atoms are attached to oxygen in an approximate angle of 105 degrees. When water is over 4 degrees the molecular motion weakens the hydrogen bonds and the oriented intermolecular interaction don’t occur. Below 4 degrees water takes their oriented bonds and their volume increase due to the geometrical conformation of these bonds.

My intention with the think experiment is to clarify for me the relation between kinetic and thermal energy, and how one can be converted into another. So, chemical quantum electron dynamics is a little out of my focus now. If complicating the model is essential to understand the kinetic/ thermal phenomena fine, if not I am just staying in the basics.
 

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