Difference between eigenvalue and an expectation value

Click For Summary
SUMMARY

The discussion clarifies the distinction between eigenvalues and expectation values in quantum mechanics. An expectation value, defined as the average of a repeated measurement, equals the eigenvalue when the system is in a pure eigenstate. Specifically, for an operator A acting on a Hilbert space H, the expectation value is calculated as a = <ψ|A|ψ>/<ψ|ψ>, while the eigenvalue is defined by the equation A|ψ> = α|ψ>. Thus, when |ψ> is an eigenstate of A, the expectation value and eigenvalue are identical.

PREREQUISITES
  • Understanding of quantum mechanics concepts, particularly operators and states.
  • Familiarity with Hilbert space notation and properties.
  • Knowledge of eigenvalues and eigenstates in linear algebra.
  • Basic grasp of expectation values in quantum theory.
NEXT STEPS
  • Study the mathematical framework of Hilbert spaces in quantum mechanics.
  • Learn about the role of operators in quantum systems, focusing on Hermitian operators.
  • Explore the implications of measurement theory in quantum mechanics.
  • Investigate the relationship between pure states and mixed states in quantum systems.
USEFUL FOR

Students and professionals in quantum mechanics, physicists exploring operator theory, and anyone seeking to deepen their understanding of eigenvalues and expectation values in quantum systems.

solas99
Messages
69
Reaction score
1
difference between eigenvalue and an expectation value of an observable. in what circumstances may they be the same?

from what i understand, an expectation value is the average value of a repeated value, it might be the same as eigen value, when the system is a pure eigenstate..

am i right?
 
  • Like
Likes   Reactions: Basirul
Physics news on Phys.org
solas99 said:
difference between eigenvalue and an expectation value of an observable. in what circumstances may they be the same?

from what i understand, an expectation value is the average value of a repeated value, it might be the same as eigen value, when the system is a pure eigenstate..

am i right?

Yes, you are right :smile:

Given an operator [itex]A: H \rightarrow H[/itex], [itex]H[/itex] an Hilbert space, [itex]|\psi\rangle \in H[/itex], then

i) [itex]a \equiv \frac{\langle \psi | A| \psi \rangle}{\langle \psi | \psi \rangle}[/itex] is the expectation value of [itex]A[/itex] over the state [itex]|\psi \rangle[/itex];
ii) if there exists [itex]\alpha \in \mathbb{C}[/itex] such that [itex]A|\psi \rangle = \alpha |\psi \rangle[/itex], then [itex]\alpha[/itex] is the eigenvalue of [itex]A[/itex] associated with the eigenstate [itex]|\psi\rangle[/itex].

So if [itex]|\psi\rangle[/itex] is an eigenstate of [itex]A[/itex] with eigenvalue [itex]\alpha[/itex] and [itex]\langle \psi|\psi\rangle=1[/itex], then [itex]a=\alpha[/itex].

Ilm
 
  • Like
Likes   Reactions: Kartik_iit_mandi, crick and (deleted member)

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K