Difference between focal length and the distance from the lens

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SUMMARY

The discussion focuses on the differences between focal length and the distance from the lens, specifically in the context of camera lenses and optical formulas. Users reference the lens formula 1/v = 1/u + 1/f, where v is the image distance, u is the object distance, and f is the focal length. The confusion arises in applying this formula correctly to various scenarios involving focal lengths of 50mm and 200mm, and lens powers of 5 diopters and 24 diopters. Participants emphasize the importance of unit consistency and correct usage of optical terminology.

PREREQUISITES
  • Understanding of lens formulas, specifically 1/v = 1/u + 1/f
  • Knowledge of optical power and diopters
  • Familiarity with focal length concepts in photography
  • Ability to convert measurements into consistent units
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  • Research the lens formula and its applications in optics
  • Learn about diopters and how to calculate lens power
  • Study the relationship between object distance, image distance, and focal length
  • Explore practical examples of focal length in photography and its effects on image quality
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Photography students, optical engineers, and anyone interested in understanding the principles of lens optics and their practical applications in imaging technology.

greener1993
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Lens and distances

I do use images as help when working theses out. going to try and scan theses in but tryed my best just using pc for now. 0 = lens F = focal length

1) a camera with a 50mm focal length lens is focused on a persons face 1m from the lense. show that the film will be about 53mm behide the lens.
(focal length = 0.05)
------------------0--F--------------
(-) (?) (1m) (+)

Simple knowledge says 1/v=1/u +1/f i then rearranged that to make 1/u=1/1 - 1/ 0.050

= 20... not 53 mm, very confused :S

2) with a zoom lens you can vary the power of a lens. show that a lens power of about 24 dioptre is required to focus a flower that is 250mm in front of the lens on a piece of film that is 50 mm behide the lens.

im extremely confused on this one. I yet again used 1/v=1/u+1/f rearranged it to make 1/u = 1/v - 1/f or 1/u= 1/0.25 - 1/24 = 3.95 :S not 50

I would think I've just messed up the equation in this one.

3)A lamp 400mm from a lens is in focus on a screen 400mm from the lens on the other side of the lens. show that the lens has a power of 5 diopters and a focal lenth of 200mm. Explain why the lamp must be moved nearer to the lens to project its image further away.

im unable to find out how they got 200mm focal lenth from there i can work out the power. 1/0.2 = 5. the wording of this question is extremely bad.

additional help

Just a couple of quick question that arnt on my homework but would like to know for background info.

whats the difference between focal lenth and the distance from the lens and why are they so different? what happens if it is not the same as the focal lenth? it is burred?


Cheers people, Thanks for looking

P.S sorry for bad spelling i have dyslexia:)
 
Last edited:
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1/u=1/1 - 1/ 0.050
Put all distances in the same units. Are you sure about that formula? I seem to remember 1/Di + 1/Do = 1/f where Di is the distance from the lens to the image, Do is the distance from the object to the lens and f is the focal length.

Better look up "dioptre" for #2. You haven't used it correctly.

#3 looks clear to me. Same formula.
 

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