- #1

- 53

- 2

Thanks

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

Or if you like, Right moving particles are expressed as:\frac{\partial \psi_R}{\partial t}=-\frac{\partial \psi_R}{\partial x}which represent right moving particles for (ω/k = +1). Left moving particles are represented by:\frac{\partial \psi_L}{\partial t}=+\frac{\partial \psi_L}{\partial x}In summary, a Weyl spinor is an ordinary 4-component complex-valued spinor representing a spin-1/2 particle like an electron which has an anti-particle, while a Majorana spinor is a real-valued spin

- #1

- 53

- 2

Thanks

Physics news on Phys.org

- #2

Science Advisor

Homework Helper

- 25,833

- 256

hi zaybu! welcome to pf!

a Weyl spinor (

a Majorana spinor is a

for details, see page 95 ff. (page 102 of the .pdf) of David Tong's "Quantum Field Theory" at http://www.damtp.cam.ac.uk/user/tong/qft/qft.pdf" [Broken]

Last edited by a moderator:

- #3

- 409

- 1

- #4

Science Advisor

Gold Member

- 2,370

- 1,409

A Majorana spinor is one that is its own antiparticle.

- #5

Science Advisor

Homework Helper

- 25,833

- 256

LAHLH said:

Yes, a 4-component spinor is make up of two 2-component spinors.

- #6

- 160

- 0

zaybu said:

Thanks

Weyl Spinors are when you have right moving and left moving waves, but are not coupled equations. For instance:

[tex]i\dot{\psi_R}=-i \partial_x \psi_R+M \psi_L[/tex]

described right moving waves. Left movers are described as thus:

[tex]i \dot{\psi_L}=+i \partial_x \psi_L+M \psi_R[/tex]

a Majorana field is a coupled equation, which happens when you introduce a mass term into the Dirac Equation:

[tex]i\dot{\psi}=-i \alpha \partial_x \psi + M\beta[/tex]

Last edited:

- #7

- 160

- 0

[tex]\frac{\partial \psi_R}{\partial t}=-\frac{\partial \psi_R}{\partial x}[/tex]

which represent right moving particles for (ω/k = +1).

Left moving particles are represented by:

[tex]\frac{\partial \psi_L}{\partial t}=+\frac{\partial \psi_L}{\partial x}[/tex]

- #8

- 160

- 0

[tex]i\dot{\psi}=-i \alpha \partial_x \psi + M\beta[/tex]

Share:

- Replies
- 10

- Views
- 808

- Replies
- 2

- Views
- 1K

- Replies
- 1

- Views
- 637

- Replies
- 1

- Views
- 540

- Replies
- 0

- Views
- 302

- Replies
- 27

- Views
- 1K

- Replies
- 14

- Views
- 4K

- Replies
- 6

- Views
- 1K

- Replies
- 3

- Views
- 561

- Replies
- 3

- Views
- 2K