Difference of Hydrogen Hamiltonian with relative mass particles

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SUMMARY

The discussion focuses on the derivation of electronic states of hydrogen using two approaches: one neglecting the proton's movement due to its relative mass and the other incorporating the proton's movement through the reduced mass, denoted as ##\mu##. The derivation using the reduced mass is more accurate, accounting for the proton's movement, which results in a minuscule shift in energy levels—approximately 1/1840 of their energy due to the proton's mass being about 1840 times that of the electron. While both Hamiltonians yield analogous results, the reduced mass approach is crucial for precision spectroscopy but irrelevant for general emission predictions.

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Abigale
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Hi guys,
I consider the qm-derivation of the electronic states of hydrogen.

There are two different derivations (I consider only the coulomb-force):

1) the proton is very heavy, so one can neglect the movement
2) the proton moves a little bit, so one uses the relative mass ##\mu##

The derivation for the 1) case is easy.

Where is the physical difference at the end of the calculations for case 1) or 2)?
Do both Hamiltonians lead to the same result?

Thank you very much!
Greez Abby
 
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The derivations are completely analogous. The one using the reduced mass is more accurate since it takes the proton into account in terms of movement. The difference is miniscule as the proton is much much heavier than the electron.
 
To quantify miniscule: the proton mass is about 1840 times the electron mass, so all energy levels shift by about 1/1840 of their energy.
Certainly important if you want to do precision spectroscopy, irrelevant if you want to know if the emission will be blue or red.
 

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