MHB Difference Quotient for Linear and Quadratic Functions

Click For Summary
The discussion focuses on evaluating the difference quotient for linear and quadratic functions. For the linear function f(x) = 2x - 3, the difference quotient simplifies to a constant value of 2. In contrast, for the quadratic function f(x) = 2x^2 - 3x, the difference quotient results in 4x - 3, which varies with x. The thread emphasizes deriving general formulas for the difference quotient before applying them to specific functions. Overall, the difference quotient provides insights into the slope of linear and quadratic functions at any point.
MarkFL
Gold Member
MHB
Messages
13,284
Reaction score
12
Here are the questions:

Evaluate the difference quotient for?

Evaluate the difference quotient for:

1) f(x)=2x-3
2) f(x)=2x^2-3x

PLEASE SHOW ALL WORK

I have posted a link there to this topic so the OP may see my work.
 
Mathematics news on Phys.org
Hello an,

Rather than work these specific problems, let's use general functions to develop theorems which we can then use to answer the questions.

i) Linear functions.

Let $$f(x)=ax+b$$

and so the difference quotient is:

$$\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=\lim_{h\to0}\frac{(a(x+h)+b)-(ax+b)}{h}=\lim_{h\to0}\frac{ax+ah+b-ax-b}{h}=\lim_{h\to0}\frac{ah}{h}=\lim_{h\to0}a=a$$

ii) Quadratic functions.

Let $$f(x)=ax^2+bc+c$$

and so the difference quotient is:

$$\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=\lim_{h\to0}\frac{\left(a(x+h)^2+b(x+h)+c \right)-\left(ax^2+bx+c \right)}{h}=$$

$$\lim_{h\to0}\frac{ax^2+2ahx+ah^2+bx+bh+c-ax^2-bx-c}{h}=\lim_{h\to0}\frac{2ahx+ah^2+bh}{h}= \lim_{h\to0}(2ax+ah+b)=2ax+b$$

Now we may answer the questions:

1.) This is a linear function. We identity $a=2,\,b=-3$ and so:

$$\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=a=2$$

2.) This is a quadratic function. We identity $a=2,\,b=-3,\,c=0$ and so:

$$\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=2ax+b=4x-3$$
 
I have been insisting to my statistics students that for probabilities, the rule is the number of significant figures is the number of digits past the leading zeros or leading nines. For example to give 4 significant figures for a probability: 0.000001234 and 0.99999991234 are the correct number of decimal places. That way the complementary probability can also be given to the same significant figures ( 0.999998766 and 0.00000008766 respectively). More generally if you have a value that...

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K