Difference Quotient for Linear and Quadratic Functions

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SUMMARY

The discussion focuses on evaluating the difference quotient for linear and quadratic functions, specifically for the functions f(x) = 2x - 3 and f(x) = 2x² - 3x. For the linear function, the difference quotient simplifies to a constant value of 2, while for the quadratic function, it results in the expression 4x - 3. The derivation of these results utilizes the limit definition of the difference quotient, demonstrating the application of calculus principles to polynomial functions.

PREREQUISITES
  • Understanding of calculus concepts, specifically limits and derivatives.
  • Familiarity with polynomial functions, including linear and quadratic forms.
  • Ability to manipulate algebraic expressions and perform simplifications.
  • Knowledge of the difference quotient and its significance in calculus.
NEXT STEPS
  • Study the concept of limits in calculus, focusing on limit definitions and properties.
  • Explore the derivative rules for polynomial functions, including the power rule.
  • Learn about the applications of the difference quotient in real-world scenarios.
  • Investigate higher-order polynomials and their difference quotients for advanced understanding.
USEFUL FOR

Students studying calculus, mathematics educators, and anyone interested in understanding the foundational concepts of derivatives and their applications to linear and quadratic functions.

MarkFL
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Here are the questions:

Evaluate the difference quotient for?

Evaluate the difference quotient for:

1) f(x)=2x-3
2) f(x)=2x^2-3x

PLEASE SHOW ALL WORK

I have posted a link there to this topic so the OP may see my work.
 
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Hello an,

Rather than work these specific problems, let's use general functions to develop theorems which we can then use to answer the questions.

i) Linear functions.

Let $$f(x)=ax+b$$

and so the difference quotient is:

$$\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=\lim_{h\to0}\frac{(a(x+h)+b)-(ax+b)}{h}=\lim_{h\to0}\frac{ax+ah+b-ax-b}{h}=\lim_{h\to0}\frac{ah}{h}=\lim_{h\to0}a=a$$

ii) Quadratic functions.

Let $$f(x)=ax^2+bc+c$$

and so the difference quotient is:

$$\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=\lim_{h\to0}\frac{\left(a(x+h)^2+b(x+h)+c \right)-\left(ax^2+bx+c \right)}{h}=$$

$$\lim_{h\to0}\frac{ax^2+2ahx+ah^2+bx+bh+c-ax^2-bx-c}{h}=\lim_{h\to0}\frac{2ahx+ah^2+bh}{h}= \lim_{h\to0}(2ax+ah+b)=2ax+b$$

Now we may answer the questions:

1.) This is a linear function. We identity $a=2,\,b=-3$ and so:

$$\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=a=2$$

2.) This is a quadratic function. We identity $a=2,\,b=-3,\,c=0$ and so:

$$\lim_{h\to0}\frac{f(x+h)-f(x)}{h}=2ax+b=4x-3$$
 

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