Differences between Raman stokes and fluorescence

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Discussion Overview

The discussion centers on the differences between Raman scattering and fluorescence, particularly in the context of resonance Raman scattering. Participants explore the mechanisms behind these phenomena, including the nature of electronic transitions involved and the concept of photon identity during these processes.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants propose that fluorescence involves re-emission of a photon with a longer wavelength due to transitions between real electronic states, while Raman scattering involves virtual electronic-vibrational transitions.
  • Others argue that fluorescence is an absorption/re-emission process, contrasting with Raman scattering as an inelastic scattering process.
  • A participant questions when a photon "loses its identity" and becomes a "re-emitted" photon, suggesting that this occurs when the photon interacts constructively with a system.
  • There is a discussion about whether resonance Raman scattering involves virtual electronic states, with one participant expressing skepticism about their involvement.

Areas of Agreement / Disagreement

Participants express differing views on the nature of photon identity and the role of virtual states in resonance Raman scattering, indicating that multiple competing views remain without consensus.

Contextual Notes

The discussion highlights potential limitations in understanding the definitions and mechanisms of fluorescence and Raman scattering, particularly regarding the assumptions about virtual states and the timing of photon interactions.

AlKindi
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If the fluorescence is the re-emitting of a photon with a larger wave length due to the transition from a higher energy state to a lower energy state in the case of resonance Raman (where there aren't any virtual states) seems be equal to the fluorescence. Which differences are there?
 
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Fluorescence occurs due to real electronic transitions, while Raman scattering occurs as a result of virtual electronic-vibrational transitions.

That is, fluorescence is an absorption/re-emission process while Raman scattering is an inelastic scattering process.

Claude.
 
Claude's answer brings up an interesting point about this problem: when does a photon "lose its identity" and become classified as a "re-emitted" photon?
 
Claude Bile said:
Fluorescence occurs due to real electronic transitions, while Raman scattering occurs as a result of virtual electronic-vibrational transitions.

That is, fluorescence is an absorption/re-emission process while Raman scattering is an inelastic scattering process.

Claude.

Thanks Claude, but what's about Resonace Raman scattering are there any virtual electronic states involve? I don't think so... [Modern Raman Spectroscopy– A Practical Approach p. 94]
 
fsonnichsen said:
Claude's answer brings up an interesting point about this problem: when does a photon "lose its identity" and become classified as a "re-emitted" photon?

I think when a photon (and the wave associeted) interact costructively with a system there is a time in which the photon "lose its identity" (e.g. the 10-5 seconds for the fluorescence) the energy is non more in the photon but in the system e.g. molecule. So we can say that it is re-emitted because of this transition I think we can also say the system (the molecule, the atoms etc. etc.) is re-formed.
 

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