From the second Friedmann equation,(adsbygoogle = window.adsbygoogle || []).push({});

$$H^2 = \frac{1}{3M_p^2} \rho \quad (k=0, flat)$$

In warm inflation, radiation is present all the way therefore not requiring proper reheating process, so

$$\rho = \rho_\phi + \rho_r \, ; \quad \rho_\phi = inflaton, \, \rho_r = radiation$$

But, $$\rho = \Big(T + V \Big)$$

What should be the kinetic and potential energy of ##\rho_r## as opposed to ##\rho_\phi = \Big(\frac{1}{2} \dot \phi^2 + V \Big)## (i.e. ##V = \frac{1}{2}m^2\phi^2##)?

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# I Different forms of energy density in inflation

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