- #1
shinobi20
- 271
- 20
From the second Friedmann equation,
$$H^2 = \frac{1}{3M_p^2} \rho \quad (k=0, flat)$$
In warm inflation, radiation is present all the way therefore not requiring proper reheating process, so
$$\rho = \rho_\phi + \rho_r \, ; \quad \rho_\phi = inflaton, \, \rho_r = radiation$$
But, $$\rho = \Big(T + V \Big)$$
What should be the kinetic and potential energy of ##\rho_r## as opposed to ##\rho_\phi = \Big(\frac{1}{2} \dot \phi^2 + V \Big)## (i.e. ##V = \frac{1}{2}m^2\phi^2##)?
$$H^2 = \frac{1}{3M_p^2} \rho \quad (k=0, flat)$$
In warm inflation, radiation is present all the way therefore not requiring proper reheating process, so
$$\rho = \rho_\phi + \rho_r \, ; \quad \rho_\phi = inflaton, \, \rho_r = radiation$$
But, $$\rho = \Big(T + V \Big)$$
What should be the kinetic and potential energy of ##\rho_r## as opposed to ##\rho_\phi = \Big(\frac{1}{2} \dot \phi^2 + V \Big)## (i.e. ##V = \frac{1}{2}m^2\phi^2##)?