Different times Reference Frame Question

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A second reference frame can exist where two events occur at the same location but at different times. The calculated speed of 1.66 x 10^8 m/s, which is below the speed of light, suggests that such a frame is possible. The approach to solving the problem is correct, but verification of the arithmetic is necessary for accuracy. The discussion emphasizes the importance of ensuring calculations align with the principles of relativity. Ultimately, confirming the arithmetic will lead to the correct identification of the second reference frame.
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Homework Statement



In a given reference frame, event 1 occurs at t1 = 0 s and position x1 = 0 m while event 2 occurs at t2 = 3.6 × 10^−4 s and x2 = 0.60 × 10^5m. Is there a second reference frame in which these events could be at the same place but different times? If so, specify its motion with respect to the first frame. If not, what is the frame in which the two events have the least possible distance.

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The Attempt at a Solution



I wasn't sure if this is how you do it, but since .60^5/3.6^-4 = 1.66 x 10^8 m/s, which is lower than the speed of light, I said a reference frame moving at that speed relative to the first one would satisfy that requirement. However, can someone confirm / refute that and give me some advice. Thank you!

Homework Statement

 
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I haven't actually checked your arithmetic, but you're thinking about the problem in the right way, so if you did the arithmetic right you'll have the right answer.
 

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