Different times Reference Frame Question

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SUMMARY

The discussion centers on determining whether there exists a second reference frame where two events occur at the same location but at different times. The events are defined by event 1 at t1 = 0 s, x1 = 0 m and event 2 at t2 = 3.6 × 10^−4 s, x2 = 0.60 × 10^5 m. The conclusion is that a reference frame moving at 1.66 x 10^8 m/s relative to the first frame can achieve this condition, as this speed is below the speed of light, thus adhering to the principles of special relativity.

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  • Familiarity with reference frames and Lorentz transformations
  • Basic knowledge of event coordinates in spacetime
  • Ability to perform calculations involving speed and time
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  • Explore the implications of simultaneity in different reference frames
  • Learn about the speed of light as a universal constant
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Homework Statement



In a given reference frame, event 1 occurs at t1 = 0 s and position x1 = 0 m while event 2 occurs at t2 = 3.6 × 10^−4 s and x2 = 0.60 × 10^5m. Is there a second reference frame in which these events could be at the same place but different times? If so, specify its motion with respect to the first frame. If not, what is the frame in which the two events have the least possible distance.

Homework Equations





The Attempt at a Solution



I wasn't sure if this is how you do it, but since .60^5/3.6^-4 = 1.66 x 10^8 m/s, which is lower than the speed of light, I said a reference frame moving at that speed relative to the first one would satisfy that requirement. However, can someone confirm / refute that and give me some advice. Thank you!

Homework Statement

 
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