Differential equation/characteristic equation

  • #1
Resa
8
0
Member warned about not using the homework template
Any help is appreciated

1.)----Find the Character equation for the diff equation d^2y/dx^2-4dy/dx+3y=0 with initial conditions y(0)=0 and y'(0)=12 find the solution y(t)

(this is what I have gotten so far on this part) p^2+4p+3=0
then (p-1)(p-3)=0 so p1=1 and p2=3?
not really sure what to do after that
2.)----then solve the diff equation 4dy/dx+16y=80 where y(0)=6 (hint is that you have the homogenous solution in the problem above)
 
Physics news on Phys.org
  • #2
Resa said:
Any help is appreciated

1.)----Find the Character equation for the diff equation d^2y/dx^2-4dy/dx+3y=0 with initial conditions y(0)=0 and y'(0)=12 find the solution y(t)

(this is what I have gotten so far on this part) p^2+4p+3=0
then (p-1)(p-3)=0 so p1=1 and p2=3?
not really sure what to do after that
You mean ##p^2 \color{red}{-} 4p +3##. You got the characteristic equation by assuming solutions of the form ##e^{pt}##. So what do you get for your general solution?
 
  • #3
ummm is it
y(t)=Cept+C2ep2t
I really don't know...
 
  • #4
LCKurtz said:
You mean ##p^2 \color{red}{-} 4p +3##. You got the characteristic equation by assuming solutions of the form ##e^{pt}##. So what do you get for your general solution?
I figured out the answers
 
  • #5
Resa said:
2.)----then solve the diff equation 4dy/dx+16y=80 where y(0)=6 (hint is that you have the homogenous solution in the problem above)
Despite the hint, I don't see that this is related to question 1 at all. Have you been able to solve this problem?
 
  • #6
Mark44 said:
Despite the hint, I don't see that this is related to question 1 at all. Have you been able to solve this problem?
yes
 
Back
Top