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Differential equation/characteristic equation

  1. Nov 18, 2014 #1
    • Member warned about not using the homework template
    Any help is appreciated

    1.)----Find the Character equation for the diff equation d^2y/dx^2-4dy/dx+3y=0 with initial conditions y(0)=0 and y'(0)=12 find the solution y(t)

    (this is what I have gotten so far on this part) p^2+4p+3=0
    then (p-1)(p-3)=0 so p1=1 and p2=3??????
    not really sure what to do after that



    2.)----then solve the diff equation 4dy/dx+16y=80 where y(0)=6 (hint is that you have the homogenous solution in the problem above)
     
  2. jcsd
  3. Nov 18, 2014 #2

    LCKurtz

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    Science Advisor
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    You mean ##p^2 \color{red}{-} 4p +3##. You got the characteristic equation by assuming solutions of the form ##e^{pt}##. So what do you get for your general solution?
     
  4. Nov 18, 2014 #3
    ummm is it
    y(t)=Cept+C2ep2t
    I really dont know...
     
  5. Nov 18, 2014 #4
    I figured out the answers
     
  6. Nov 18, 2014 #5

    Mark44

    Staff: Mentor

    Despite the hint, I don't see that this is related to question 1 at all. Have you been able to solve this problem?
     
  7. Nov 18, 2014 #6
    yes
     
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