Find the solution of the diff eq that satisfies the given initial coordinate
xcosx=(2y + e^(3y)) y' , y(0)=0
The Attempt at a Solution
So I have the family of solutions:
xsinx-cosx=y^2 + e^(3y)/3 + c
and I know to put 0 in for the x's, but the solution is wrong, and it appears like I need to put 0 into the y's (yes I did say y's) but not sure why.