Differential equations problem

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The problem involves finding functions f(x) such that the area of two regions formed by a curve and rectangles parallel to the coordinate axes are in a specific ratio. The initial solution presented is f(x) = cx, where c is a real number, but the discussion suggests there may be additional solutions. The area calculations lead to the equation xf(x) = (n+1)∫_0^x f(t) dt, which is differentiated to derive a differential equation. This results in the equation x(df/dx) = n f(x), which is separable and can be integrated to find more potential functions. The exploration focuses on identifying all functions that satisfy the given area condition.
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Homework Statement


A curve with Cartesian equation y=f(x) passes through the origin. Lines drawn parallel to the coordiante axes through and arbitrary poing of the curve form a rectangle with two sides on the axes. The curve divides every such rectangle into two regions A and B, one of which has and area equal to n times the other. Find all such functions f.


Homework Equations





The Attempt at a Solution



Obviously f(x)=cx where c is a real number works, but there must be others. Any ideas?
 
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\intydx (from 0 to x) = kxy ( for k = +- 1/n+1 or n/n+1).
This gives y = k(x y' + y) ; hence y =const. x^(1-k)
 
The area below the curve is, of course, \int_0^{x} f(t)dt while the area above the curve is \int_0^{x} f(x)- f(t) dt= xf(x)- \int_0^{x} f(t) dt Saying one is n times the other means that n\int_0^{x}f(t)dt= xf(x)- \int_0^x f(t)dt so xf(x)= (n+1)\int_0^x f(t) dt.

Differentiating both sides of that with respect to x will give you a differential equation for f(x)- xdf/dx+ f(x)= (n+1)f(x) so that xdf/dx= n f(x). That is separable and easily integrable.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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