1. A body of mass 2kg is initially at rest and is acted upon by a force of (v - 4) newtons where v is the velocity in m/s. The body moves in a straight line as a result of the force. 2. a. Show that the acceleration of the body is given by dv/dt = (v - 4) / 2 b. Solve the differential equation in part a to find v as a function of t. 3. a. I used the formula F = ma where F = (v - 4) and m = 2 (v - 4) = 2a a = (v - 4) / 2 b. I tried to solve it like any other differential equation with the following initial conditions: when t = 0, v = 0 But I found it very difficult and challenging: dv/dt = (v - 4) / 2 2 dv/dt = v - 4 2 / dt = (v - 4) / dv I want to change the division sign to a multiplication sign so that I can take the integral of both sides, but I don't know how to algebraically manipulate it to be in that form.