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**1. A body of mass 2kg is initially at rest and is acted upon by a force of (v - 4) newtons where v is the velocity in m/s. The body moves in a straight line as a result of the force.**

**2. a. Show that the acceleration of the body is given by dv/dt = (v - 4) / 2**

b. Solve the differential equation in part a to find v as a function of t.

b. Solve the differential equation in part a to find v as a function of t.

**3. a. I used the formula F = ma where F = (v - 4) and m = 2**

(v - 4) = 2a

a = (v - 4) / 2

b. I tried to solve it like any other differential equation with the following initial conditions:

when t = 0, v = 0

But I found it very difficult and challenging:

dv/dt = (v - 4) / 2

2 dv/dt = v - 4

2 / dt = (v - 4) / dv

I want to change the division sign to a multiplication sign so that I can take the integral of both sides, but I don't know how to algebraically manipulate it to be in that form.

(v - 4) = 2a

a = (v - 4) / 2

b. I tried to solve it like any other differential equation with the following initial conditions:

when t = 0, v = 0

But I found it very difficult and challenging:

dv/dt = (v - 4) / 2

2 dv/dt = v - 4

2 / dt = (v - 4) / dv

I want to change the division sign to a multiplication sign so that I can take the integral of both sides, but I don't know how to algebraically manipulate it to be in that form.