Differential Form on Product Manifold

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SUMMARY

The discussion centers on the proof that the sum of two k-forms, w and w', defined on product manifolds M and N, respectively, results in a k-form on the product manifold MxN. The proof utilizes the isomorphism of tangent spaces, specifically T_{(m,n)}(M×N) = T_m M ⊕ T_n N, and its dualization to establish that (T_{(m,n)}(M × N))^* = (T_m M)^* ⊕ (T_n N)^*. This confirms that the operation of taking the direct sum of forms is valid in the context of product manifolds.

PREREQUISITES
  • Understanding of differential forms and their properties
  • Familiarity with product manifolds and tangent spaces
  • Knowledge of dual spaces and isomorphisms in linear algebra
  • Basic concepts of vector fields in differential geometry
NEXT STEPS
  • Study the properties of differential forms on product manifolds
  • Explore the concept of exterior algebra and its applications
  • Learn about the implications of the Whitney sum theorem in differential geometry
  • Investigate the role of k-forms in integration on manifolds
USEFUL FOR

Mathematicians, differential geometers, and students studying advanced calculus or manifold theory will benefit from this discussion, particularly those focusing on the properties of differential forms and product manifolds.

WWGD
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Hi, I have an exercise whose solution seems too simple; please double-check my work:

We have a product manifold MxN, and want to show that if w is a k-form in M and

w' is a k-form in N, then ##(w \bigoplus w')(X,Y)## , for vector fields X,Y in M,N respectively,

is a k-form in MxN.

I am assuming k=1 , and then we can generalize. My proof:

We start with (the isomorphism):

##(T_{(m,n)}(M\times N) = (T_m M \bigoplus T_n N)##,

Then, dualizing both sides:##(T_{(m,n)} (M \times N))^* =(T_m M \bigoplus T_n N)^*##.

We then use that ##(A \bigoplus B)^*= A^* \bigoplus B^*## , to get :

##(T_{(m,n)} (M \times N))^* = (T_m M )^*\bigoplus (T_n N)^* ##.

Is that all there is to it?
 
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