Differential geometry - strange formula

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SUMMARY

The discussion focuses on the interpretation of specific formulas in differential geometry, particularly those found in Konstanty Radziszewski's book "Wstęp do współczesnej geometrii różniczkowej." The Kronecker delta, denoted as δ^i_j, represents the identity matrix's entries, being 1 when i equals j and 0 otherwise. Additionally, the metric tensor g_{ij} is introduced as a crucial component in the scalar product of vectors, illustrating the transition from basic vector notation to more complex tensor operations.

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heeello friends!;]
i have book "wstęp do współczesnej geometrii różniczkowej" written by Konstanty Radziszewski, this title in english mean something like... "basics of modern differential geometry", and here are many formulas which look similar to one another, but I never know what it means and sometimes its difficult to understand this, examples:
A^{i^\prime}_iA^j_{i^\prime}=\delta^i_j
what this delta means? here is written that its 1 when i=j and 0 when i\neq j, but I don't know what it means, this multiplication value is just 1 or 0 depending on this value?
next problem:) I have formula for skalar multiplication of two vectors: \partial\mbox{x}(u)=\mbox{x}_i(u)\partial u_x^i,\quad\delta\mbox{x}(u)=\mbox{x}_i(u)\delta u_x^i
and the formula:
\partial\mbox{x}(u)\delta\mbox{x}(u)=\mbox{x}_i(u)\mbox{x}_j(u)\partial u_x^i\delta u_x^j=g_{ij}(u)\partial u_x^i\delta u_x^j
why in upper equation there is "i" in upper index, and then suddenly "j" in next formula? what happened after last equation? why there is suddenly g_{ij}(u) instead of \mbox{x}_i(u)\mbox{x}_j(u)? what it means?
thanks for answer mathematicians;]
 
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I'm relatively new to these ideas myself, and don't know what all of the notation means, but perhaps this answers part of your question. Hopefully someone more knowledgeable than me can give you a better and more thorough explanation than I can.

You can think of \delta^i_j (called "Kronecker's delta" or "the Kronecker delta") as the entries of the identity matrix, if you treat the upper index as the indicating the row, and the lower index as indicating the column: the nxn matrix with 1 for each entry of its main diagonal, and zeros everywhere else, where n is how many values an index can take. So for n = 3,

\begin{bmatrix}<br /> 1 &amp; 0 &amp; 0\\ <br /> 0 &amp; 1 &amp; 0\\ <br /> 0 &amp; 0 &amp; 1<br /> \end{bmatrix}

If i = j (row 1, column 1; row 2, column 2; row 3, column 3), then the entry is 1, otherwise it's zero (row 1, column 2, etc.).

For example, if i can be 1 or 2, then n = 2, and

A^i\enspace_k B^k\enspace_j = \delta^i_j

would stand for a set of n2 = 4 equations:

\sum_{k=1}^{2} A^1\enspace_k B^k\enspace_1 = \delta^1_1

\sum_{k=1}^{2} A^1\enspace_k B^k\enspace_2 = \delta^1_2

\sum_{k=1}^{2} A^2\enspace_k B^k\enspace_1 = \delta^2_1

\sum_{k=1}^{2} A^2\enspace_k B^k\enspace_2 = \delta^1_2

which we can express more neatly as a single matrix equation

AB = I = \begin{bmatrix}<br /> 1 &amp; 0\\ <br /> 0 &amp; 1<br /> \end{bmatrix}

where I is the identity matrix.

g_{ij} is called the metric tensor. If a and b are vectors, with components a^i = \left( a^1, a^2, ..., a^n \right), and b^j = \left( b^1,b^2,...,b^n \right), then their scalar product is

g_{ij}a^ib^j = a_jb^j = a^ib_i

which is just a quick way of writing

\sum_{i=1}^{n} \sum_{j=1}^{n} g_{ij}a^i b^j.
 

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