Differential gravitational force causing tides model?

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Homework Help Overview

The discussion revolves around understanding the differential gravitational forces exerted by the moon and their role in creating tides on Earth. Participants are exploring the gravitational interactions and the implications of Earth's rotation in this context.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to analyze the gravitational force components acting on the Earth due to the moon, considering angles and symmetry. They express confusion about how to proceed with the calculations and the relevance of equipotential surfaces. Other participants question the necessity of focusing solely on forces versus potentials and discuss the implications of Earth's rotation on tidal forces.

Discussion Status

Participants are actively engaging with the problem, raising questions about the use of gravitational potentials and the effects of Earth's rotation. Some guidance has been offered regarding the application of Newton's law of gravity to create a potential due to the moon, but no consensus has been reached on the best approach to take.

Contextual Notes

There is an indication that the problem may involve assumptions about the symmetry of tidal forces and the effects of Earth's motion in relation to the moon, which are being discussed but not resolved.

21joanna12
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Homework Statement


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Homework Equations

The Attempt at a Solution


For a), I initially tried to consider the component of the gravitational force of the moon acting normally to the Earth's surface. This would be F=F_0 cos(theta) where theta is the angle between a horizontal line going through A and B and the point on the Earth's surface in question (giving zero at the poles and maximum at the equator). I know that , due to the effect of the Earth actually undergoing circular motion and 'free-falling' due to the moon's gravitational pull, the force at each point on the side of the Earth facing the moon will be (approximately) mirrored by the opposite side of the Earth since r<<x. But now I am stuck. I wanted to deal with forces rather than equipotentials, as it seems like the question wants you to just deal with the forces. I was considering the fact that the effect is actually spherically symmetrical when looking onto the face of the Earth from the moon, but II don't know what to do with this to find the heights? I could find the total volume of water on the Earth by doing surface area of Earth x 750, but I still don't see how II could use this?Thank you in advance :)
 
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21joanna12 said:
as it seems like the question wants you to just deal with the forces
I don't see why. Potentials are fine.
 
mfb said:
I don't see why. Potentials are fine.

Help! I cannot figure out how to get the equation with the equipotential. Would I have to consider the Earth's rotation? And how to I create a potential due to the moon?
 
21joanna12 said:
And how to I create a potential due to the moon?
In the same way you do for earth, with Newton's law of gravity.
21joanna12 said:
Would I have to consider the Earth's rotation?
Not the 24h-rotation, but the motion around the center of mass of the earth/moon system is relevant to get the second tidal wave at the opposite side.
 

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