Differentiating a definite integral

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SUMMARY

The discussion centers on the differentiation of a definite integral, specifically the expression \(\frac{\partial}{\partial t}{\int_0^t}{\int_0^1}u_t^2(x,s)dx ds\). The participant seeks clarification on the differentiation process, particularly regarding the application of the fundamental theorem of calculus and the chain rule. The conclusion emphasizes that if \(u\) depends on \(t\), the differentiation can be performed by dropping the outer integral and replacing \(s\) with \(t\), leading to the result \(\int_0^1}u_t^2(x,t)dx + \int_0^t}{\int_0^1}\frac{\partial}{\partial t}u_t^2(x,s)dx ds\).

PREREQUISITES
  • Understanding of definite integrals and their properties
  • Familiarity with the fundamental theorem of calculus
  • Knowledge of partial differentiation
  • Basic concepts of multivariable functions
NEXT STEPS
  • Study the fundamental theorem of calculus in detail
  • Learn about the chain rule in the context of multivariable calculus
  • Explore applications of differentiation under the integral sign
  • Investigate examples of differentiating definite integrals with variable limits
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Students and professionals in mathematics, particularly those studying calculus, as well as researchers needing to differentiate complex integral expressions.

gaganaut
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I was reading on a textbook and came across a step and I had no idea how the author got the next step from it. This was basically differentiation of a definite integral.

So here it is.

[tex]\frac{\partial}{\partial t}{\int_0^t}{\int_0^1}u_t^2(x,s)dx ds[/tex]

So I figured that [tex]u_t=\frac{\partial u}{\partial t}[/tex]. But isn't there a simple rule to differentiate an integral like this. I can probably get away with just using the final result from the book in my research, but not knowing how I got to it is just something that is bugging me.

So any help will be much appreciated.

Thanks
 
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What is the meaning of ut ?
You write u(x,s). Is it a three argument function u(x,s,t) ?
 
Barring that u depends on t, the fundamental theorem of calculus will just drop the outer integral and replace s with t. Otherwise I think its valid to apply the chain rule in this fashion
[tex]\frac{\partial}{\partial t}{\int_0^t}{\int_0^1}u_t^2(x,s)dx ds = }{\int_0^1}u_t^2(x,t)dx + {\int_0^t}{\int_0^1}\frac{\partial}{\partial t}u_t^2(x,s)dx ds[/tex]
 

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