Differentiating a power series

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Homework Help Overview

The discussion revolves around differentiating the power series for the function ##\frac{1}{1-x}## to derive the power series for ##\frac{1}{(1-x)^2}##. Participants explore the representation of power series and their differentiation.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the power series for ##\frac{1}{1-x}## and its differentiation, with some providing the series expansion and others confirming the correctness of the approach.

Discussion Status

The discussion appears to be progressing positively, with participants affirming each other's contributions and suggesting alternative representations of the series.

Contextual Notes

There is a note that the summation index for the differentiated series starts at n = 1, which may influence the interpretation of the results.

Poetria
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Homework Statement


[/B]
Differentiate the power series for ##\frac 1 {1-x}## to find the power series for ##\frac 1 {(1-x)^2}##
(Note the summation index starts at n = 1)

2. The attempt at a solution


##\sum_{n=1}^\infty n*x^{n-1}##
 
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What is the power series for 1/(1-x) ?
 
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BvU said:
What is the power series for 1/(1-x) ?

##\sum_{n=0}^\infty x^n##

OK?

Series expansion at x = 0
1+x+x^2+x^3...

So if I differentiate:

0+1+2*x+3x^3...
 
Good. Perfect, in fact. If you want you can rewrite it in a more conventional form (##\ \ \displaystyle\sum_{n=0}^\infty \ \ ##)
 
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BvU said:
Good. Perfect, in fact. If you want you can rewrite it in a more conventional form (##\ \ \displaystyle\sum_{n=0}^\infty \ \ ##)

Ok. :) Many thanks. :)

##\sum_{n=0}^\infty (n+1)*x^n##
 
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