Differentiating a trignometric function

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SUMMARY

The discussion centers on the differentiation of a trigonometric function involving the secant function. The user presents the equation $$\d{x}{t} = 20 \sec^2 \delta \d{\delta}{t}$$ and questions the emergence of the cosine term in the transformation to $$\d{\delta}{t} = \frac{1}{20} \cos^2 \delta \d{x}{t}$$. The response clarifies that the cosine term arises from the definition of the secant function, specifically $$\sec \delta = \frac{1}{\cos \delta}$$, establishing a direct relationship between secant and cosine in trigonometric identities.

PREREQUISITES
  • Understanding of basic trigonometric functions, specifically secant and cosine.
  • Familiarity with differentiation in calculus.
  • Knowledge of trigonometric identities and their applications.
  • Ability to manipulate equations involving derivatives.
NEXT STEPS
  • Study the relationship between secant and cosine functions in trigonometry.
  • Explore differentiation techniques for trigonometric functions.
  • Learn about trigonometric identities and their proofs.
  • Practice solving differential equations involving trigonometric functions.
USEFUL FOR

Students of calculus, mathematics educators, and anyone interested in understanding the differentiation of trigonometric functions and their identities.

tmt1
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So, I have

$$\d{x}{t} = 20 sex^2∂ \d{∂}{t}$$

And the text goes to:

$$ \d{∂}{t} = \frac{1}{20}cos^2 ∂ \d{x}{t}$$

I don't understand where the cos comes from? Is it a trigonometric identity? If so I can't find it.
 
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tmt said:
So, I have

$$\d{x}{t} = 20 sex^2∂ \d{∂}{t}$$

And the text goes to:

$$ \d{∂}{t} = \frac{1}{20}cos^2 ∂ \d{x}{t}$$

I don't understand where the cos comes from? Is it a trigonometric identity? If so I can't find it.

Hi tmt!

By definition:
$$\sec \delta = \frac{1}{\cos\delta}$$
 

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