Differentiating Lorentz factor with respect to time

  • #1

Homework Statement


I would like some help on differentiating the lorentz factor with respect to time


Homework Equations





The Attempt at a Solution



i arrived at [tex] (-1/2) (1-v^2/c^2)^{-3/2} [/tex]
but a forum on this website says it is [tex] (-1/2) (1-v^2/c^2)^{-3/2} ( \frac{-2v}{c^2} dv/dt)[/tex]

Please help!
 

Answers and Replies

  • #2
cristo
Staff Emeritus
Science Advisor
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You want [tex]\frac{d}{dt}(1-v^2/c^2)^{-1/2}[/tex]. Using the chain rule, this is equal to [tex] \frac{d}{dv}(1-v^2/c^2)^{-1/2}\frac{dv}{dt}=\left(\frac{-1}{2}\right)\left(\frac{-2v}{c^2}\right)(1-v^2/c^2)^{-3/2}\frac{dv}{dt}[/tex]

Does that help?
 
  • #3
Thnx a ton cristo!Just cudnt think about it
 

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