- #1

ChiralSuperfields

- 1,187

- 132

- Homework Statement
- Please see below

- Relevant Equations
- ## E = \frac {1}{2}mv^2 + \frac {1}{2}kx^2 ##

Why when we differentiate ## E = \frac {1}{2}mv^2 + \frac {1}{2}kx^2 ## with respect to time the answer is ## \frac {dE}{dt} = mva + kxv ##?

I though it would be ##\frac {dE}{dt} = ma + kv ##.

Many thanks!

I though it would be ##\frac {dE}{dt} = ma + kv ##.

Many thanks!